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open image file from cell value
Hi
I want to be able to open an image file (jpg) based on the value of a cell. I got as far as: Sub OpenFileButton1_Click() Workbooks.Open "C:\myfiles" & ActiveSheet.Range("C2").Value End Sub which opens an xls file (e.g. 1.xls) in the c:\myfiles folder. but what code should I be using if I want to open e.g. 1.jpg in the same folder Thanks for all your help! -- --------- Gareth |
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