selection(selection.count).row
selection(selection.count).column

--
Regards,
Tom Ogilvy

"Neal Zimm" wrote in message
...
Thanks so much for the speedy reply, I'll try this out as soon as I finish
this reply.
I'm sure you know this, but I wrote the following 'on a lark'

Dim text As String
text = Selection.Address
MsgBox text

and it yielded: $D$5:$I$9

the thought of writing or stealing a routine to parse the answer was not
thrilling.
Again, Thanks.
Neal Z.





"Bob Phillips" wrote:

You could try

With Selection
row = .Cells(1,1).Row + .Rows.Count - 1
col = .Cells(1,1).Column + .Columns.Count - 1
End With

--

HTH

RP
(remove nothere from the email address if mailing direct)


"Neal Zimm" wrote in message
...
Thanks, much, and I HATE being a pest like this, but what about the
cell
in
the lower right? I need to know the 'size' of the selected range.
Since
I
wrote you this morning, I tried the loop you mentioned to 'someguy'
and
was
able to make each cell the activecell and use the max function to trap
the
highest row and column values but I'm hopeful there's a better way.
I'll
see what Excel has on the keyword 'selection' in the interim.
Thanks in advance, again,
Neal Z


"Bob Phillips" wrote:

Neal,

When you have a multi-cell selection, just get the first cell, like

row = Selection.Cells(1,1).Row

col = Selection.Cells(1,1).Column

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