I have a database, where in the first column some cells are merged (by
2, 3 or more) and some are not. I want to number them in order that
every single or "group-of-merged-cells" cell will have just one
number. Excel says that autonumbering could be applied only to cells
with the same size.

For example, first cell is single, 2nd + 3rd are merged, 4th is single
and 5th+6th+7th are merged. This way about 10000 rows in first column.
How to number them in order?

I have a VBA script to number them, but (in the example above) first
has number one, second has number two, BUT third (it is row number 4!)
has number 4 = they are numbered from the first cell of the merged
group. It is wrong, on the 4th row it has to be a "3".

Huh, apologise my poor english, I hope the problem is set clear ;o)

Thank you for answer,
Imagino

Sub numberCells()
Dim i As Long, j As Long
i = 1
j = 1
Do
If Cells(i, "B").MergeArea.Rows.Count 1 Then
Cells(i, "B").Value = j
i = i + Cells(i, "B").MergeArea.Rows.Count
Else
Cells(i, "B").Value = j
i = i + 1
End If
j = j + 1
Loop Until j 20
End Sub

might be a possibility.

As written it goes down column B. Change to reflect your column. Adjust i
to reflect the row you want to start in. and change 20 to indicate when to
stop numbering.

--
Regards,
Tom Ogilvy

"Imagino" wrote in message
om...
I have a database, where in the first column some cells are merged (by
2, 3 or more) and some are not. I want to number them in order that
every single or "group-of-merged-cells" cell will have just one
number. Excel says that autonumbering could be applied only to cells
with the same size.

For example, first cell is single, 2nd + 3rd are merged, 4th is single
and 5th+6th+7th are merged. This way about 10000 rows in first column.
How to number them in order?

I have a VBA script to number them, but (in the example above) first
has number one, second has number two, BUT third (it is row number 4!)
has number 4 = they are numbered from the first cell of the merged
group. It is wrong, on the 4th row it has to be a "3".

Huh, apologise my poor english, I hope the problem is set clear ;o)

Thank you for answer,
Imagino