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#1
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can't find a correct formula
Hi...
This is what I want ItemA 6hours 6 8 9 6 7 ItemB 6hours 7 7 6 8 8 ItemC 6hours 7 8 6 6 8 ItemD 1 hour 5 8 6 7 8 First 3 items are 6 times as important then TemD I have to calculate a % This is my current formula: (SUM(D1:E8)*100/COUNT(D1:E8))/10 This formula however calculates all items as "heavy" How should I solve this problem and.... What if all cells of ItemD are empty??? Then I devide by 0 and get an errormessage. Thanks |
#2
Posted to microsoft.public.excel.programming
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can't find a correct formula
Hi
try =IF(COUNT(B1:E8),AVERAGE(D1:E8)*10,"") -- Regards Frank Kabel Frankfurt, Germany "Jean-Paul De Winter" schrieb im Newsbeitrag ... Hi... This is what I want ItemA 6hours 6 8 9 6 7 ItemB 6hours 7 7 6 8 8 ItemC 6hours 7 8 6 6 8 ItemD 1 hour 5 8 6 7 8 First 3 items are 6 times as important then TemD I have to calculate a % This is my current formula: (SUM(D1:E8)*100/COUNT(D1:E8))/10 This formula however calculates all items as "heavy" How should I solve this problem and.... What if all cells of ItemD are empty??? Then I devide by 0 and get an errormessage. Thanks |
#3
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can't find a correct formula
I also get an errormessage when cells are empty...
Also the formula I currently use wasn't correct... it should have been: =(SUM(E6:I8)*6+SUM(E9:I9))*100/950 JP "Frank Kabel" schreef in bericht ... Hi try =IF(COUNT(B1:E8),AVERAGE(D1:E8)*10,"") -- Regards Frank Kabel Frankfurt, Germany "Jean-Paul De Winter" schrieb im Newsbeitrag ... Hi... This is what I want ItemA 6hours 6 8 9 6 7 ItemB 6hours 7 7 6 8 8 ItemC 6hours 7 8 6 6 8 ItemD 1 hour 5 8 6 7 8 First 3 items are 6 times as important then TemD I have to calculate a % This is my current formula: (SUM(D1:E8)*100/COUNT(D1:E8))/10 This formula however calculates all items as "heavy" How should I solve this problem and.... What if all cells of ItemD are empty??? Then I devide by 0 and get an errormessage. Thanks |
#4
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can't find a correct formula
Hi
my formula should return a blank cell if all cells are empty. what have you tried exactly Your formula should not return an error as you don't divide at all by zero -- Regards Frank Kabel Frankfurt, Germany "Jean-Paul De Winter" schrieb im Newsbeitrag ... I also get an errormessage when cells are empty... Also the formula I currently use wasn't correct... it should have been: =(SUM(E6:I8)*6+SUM(E9:I9))*100/950 JP "Frank Kabel" schreef in bericht ... Hi try =IF(COUNT(B1:E8),AVERAGE(D1:E8)*10,"") -- Regards Frank Kabel Frankfurt, Germany "Jean-Paul De Winter" schrieb im Newsbeitrag ... Hi... This is what I want ItemA 6hours 6 8 9 6 7 ItemB 6hours 7 7 6 8 8 ItemC 6hours 7 8 6 6 8 ItemD 1 hour 5 8 6 7 8 First 3 items are 6 times as important then TemD I have to calculate a % This is my current formula: (SUM(D1:E8)*100/COUNT(D1:E8))/10 This formula however calculates all items as "heavy" How should I solve this problem and.... What if all cells of ItemD are empty??? Then I devide by 0 and get an errormessage. Thanks |
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