Hello,

Does anyone know how to create a formula that will allow
for a begining balance of $0.00 and then take away $20.00
to give you an ending balance of -$20.00. And then have
a begining balance of $-20.00 and take away $20.00 for a
total of -40.00 instead of $0.00. I keep getting a zero.

One way:

A1: 0
A2: 20

B1: =A1 - A2 ==== -20
B2: =B1 - A2 ==== -40



In article ,
"Jessie" wrote:

Hello,

Does anyone know how to create a formula that will allow
for a begining balance of $0.00 and then take away $20.00
to give you an ending balance of -$20.00. And then have
a begining balance of $-20.00 and take away $20.00 for a
total of -40.00 instead of $0.00. I keep getting a zero.

What formula are you using?
Are you subtracting or adding the $20?

"Jessie" wrote:

Hello,

Does anyone know how to create a formula that will allow
for a begining balance of $0.00 and then take away $20.00
to give you an ending balance of -$20.00. And then have
a begining balance of $-20.00 and take away $20.00 for a
total of -40.00 instead of $0.00. I keep getting a zero.

Hi Jessie;

In VBA you can dim the value as an Interger or a Long, do
the math in memory and then write it to a cell. An
example might be

Sub try()

MyValue = Int(activecell) - 20
activecell = MyValue

End Sub

Thanks

Greg

-----Original Message-----
Hello,

Does anyone know how to create a formula that will allow
for a begining balance of $0.00 and then take away $20.00
to give you an ending balance of -$20.00. And then have
a begining balance of $-20.00 and take away $20.00 for a
total of -40.00 instead of $0.00. I keep getting a zero.
.

Hi Greg,

Since Jessie is clearly dealing with currency calculations, it would not
seem appropriate to dim your variable as either long or integer.

Further, why would you advocate using the Int function?

---
Regards,
Norman



"GJones" wrote in message
...
Hi Jessie;

In VBA you can dim the value as an Interger or a Long, do
the math in memory and then write it to a cell. An
example might be

Sub try()

MyValue = Int(activecell) - 20
activecell = MyValue

End Sub

Thanks

Greg

-----Original Message-----
Hello,

Does anyone know how to create a formula that will allow
for a begining balance of $0.00 and then take away $20.00
to give you an ending balance of -$20.00. And then have
a begining balance of $-20.00 and take away $20.00 for a
total of -40.00 instead of $0.00. I keep getting a zero.
.

Actually, for a completely different reason, Long might well be a good
way to go.

Longs will avoid many of the problems introduced by small rounding
errors in IEEE double precision floating point math. Values can be
internally multiplied and divided by 100 to match the currency
requirements.


So try() could be rewritten:

Public Sub try()
Dim MyValue As Long
With ActiveCell
MyValue = .Value * 100& - 2000&
.Value = MyValue \ 100&
End With
End Sub

However, I don't think that was the original responder's intention.


In article ,
"Norman Jones" wrote:

Since Jessie is clearly dealing with currency calculations, it would not
seem appropriate to dim your variable as either long or integer.

Further, why would you advocate using the Int function?

Hi JE,

Longs will avoid many of the problems introduced by small rounding
errors in IEEE double precision floating point math. Values can be
internally multiplied and divided by 100 to match the currency
requirements.

Excellent and well-made point!

---
Regards,
Norman

Personal preference is to use the "Currency" data type to help avoid the
small rounding issues. Depending of course on what one is doing...
Dana DeLouis

"JE McGimpsey" wrote in message
...
Actually, for a completely different reason, Long might well be a good
way to go.

Longs will avoid many of the problems introduced by small rounding
errors in IEEE double precision floating point math. Values can be
internally multiplied and divided by 100 to match the currency
requirements.


So try() could be rewritten:

Public Sub try()
Dim MyValue As Long
With ActiveCell
MyValue = .Value * 100& - 2000&
.Value = MyValue \ 100&
End With
End Sub

However, I don't think that was the original responder's intention.


In article ,
"Norman Jones" wrote:

Since Jessie is clearly dealing with currency calculations, it would not
seem appropriate to dim your variable as either long or integer.

Further, why would you advocate using the Int function?