I'd examine the value using Mid, then check to see if the Ascii code for
the extracted string lay in the correct range:

Dim str As String
str = Sheet1.Cells(1, 1).Value
If (str < "") Then
If (Asc(Mid(str, 2, 1)) 47 And Asc(Mid(str, 2, 1)) < 58)
Then
Sheet1.Cells(1, 2).Value = True
Else
Sheet1.Cells(1, 2).Value = False
End If
End If

There are probably vastly better ways of doing this though...


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Message posted from http://www.ExcelForum.com/

You may have noticed I got it the wrong way round.
Anyway, here it is again but correct, a bit neater & with more
validation:

Dim str As String
str = Sheet1.Cells(1, 1).Value
If (str < "") And (Len(str) 1) Then
Sheet1.Cells(1, 2).Value = Not (Asc(Mid(str, 2, 1)) 47 And
Asc(Mid(str, 2, 1)) < 58)
End If



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Message posted from http://www.ExcelForum.com/