If I exectue this simple code :

Range("F8").Select
ActiveCell.FormulaR1C1 = "=RC[-4]-RC[-2]"

It works great if I execute if from the current workbook but if the code is
in another workbook and I include:
Windows("Libro1").Activate

It raises error 1004

Any help?

Hello Jordi,

Check if the sheet that get the entry is not protected (Tools|Protection).
If it is protected you may want to include this into your code before the
entry

Activesheet.Unprotect
....you code here
Activesheet.Protect

If it is has password you need to type the password after the "Unprotect"
and "Protect".

Regards,

Jon-jon

"Jordi" wrote in message
...
If I exectue this simple code :

Range("F8").Select
ActiveCell.FormulaR1C1 = "=RC[-4]-RC[-2]"

It works great if I execute if from the current workbook but if the code
is
in another workbook and I include:
Windows("Libro1").Activate

It raises error 1004

Any help?

Isn't the case
but thank you.
Any other idea?

"JON JON" escribió en el mensaje
...
Hello Jordi,

Check if the sheet that get the entry is not protected (Tools|Protection).
If it is protected you may want to include this into your code before the
entry

Activesheet.Unprotect
...you code here
Activesheet.Protect

If it is has password you need to type the password after the "Unprotect"
and "Protect".

Regards,

Jon-jon

"Jordi" wrote in message
...
If I exectue this simple code :

Range("F8").Select
ActiveCell.FormulaR1C1 = "=RC[-4]-RC[-2]"

It works great if I execute if from the current workbook but if the code
is
in another workbook and I include:
Windows("Libro1").Activate

It raises error 1004

Any help?

I am trying to duplicate your scenario but could not get the same error.
Have you tried to debug? Where does the highlight go? I am suspecting that
it has something to do with the activate and select command. You may want
to avoid that and instead try something like

Workbooks("Book1").Sheets("Sheet1").Range("F8").Fo rmulaR1C1 =
"=RC[-4]-RC[-2]"


"Jordi" wrote in message
...
Isn't the case
but thank you.
Any other idea?

"JON JON" escribió en el mensaje
...
Hello Jordi,

Check if the sheet that get the entry is not protected
(Tools|Protection).
If it is protected you may want to include this into your code before
the
entry

Activesheet.Unprotect
...you code here
Activesheet.Protect

If it is has password you need to type the password after the
"Unprotect"
and "Protect".

Regards,

Jon-jon

"Jordi" wrote in message
...
If I exectue this simple code :

Range("F8").Select
ActiveCell.FormulaR1C1 = "=RC[-4]-RC[-2]"

It works great if I execute if from the current workbook but if the
code
is
in another workbook and I include:
Windows("Libro1").Activate

It raises error 1004

Any help?

try is with "book1.xls" assuming that it is OPEN.

--
Don Guillett
SalesAid Software

"JON JON" wrote in message
...
I am trying to duplicate your scenario but could not get the same error.
Have you tried to debug? Where does the highlight go? I am suspecting
that
it has something to do with the activate and select command. You may want
to avoid that and instead try something like

Workbooks("Book1").Sheets("Sheet1").Range("F8").Fo rmulaR1C1 =
"=RC[-4]-RC[-2]"


"Jordi" wrote in message
...
Isn't the case
but thank you.
Any other idea?

"JON JON" escribió en el mensaje
...
Hello Jordi,

Check if the sheet that get the entry is not protected
(Tools|Protection).
If it is protected you may want to include this into your code before
the
entry

Activesheet.Unprotect
...you code here
Activesheet.Protect

If it is has password you need to type the password after the
"Unprotect"
and "Protect".

Regards,

Jon-jon

"Jordi" wrote in message
...
If I exectue this simple code :

Range("F8").Select
ActiveCell.FormulaR1C1 = "=RC[-4]-RC[-2]"

It works great if I execute if from the current workbook but if the
code
is
in another workbook and I include:
Windows("Libro1").Activate

It raises error 1004

Any help?

I try both "Book1" and "Book1.xls" they will both work if the file is save
for the first time. However, if it is a new workbook, "Book1.xls" give me
subscript out range error.


"Don Guillett" wrote in message
...
try is with "book1.xls" assuming that it is OPEN.

--
Don Guillett
SalesAid Software

"JON JON" wrote in message
...
I am trying to duplicate your scenario but could not get the same error.
Have you tried to debug? Where does the highlight go? I am suspecting
that
it has something to do with the activate and select command. You may
want
to avoid that and instead try something like

Workbooks("Book1").Sheets("Sheet1").Range("F8").Fo rmulaR1C1 =
"=RC[-4]-RC[-2]"


"Jordi" wrote in message
...
Isn't the case
but thank you.
Any other idea?

"JON JON" escribió en el mensaje
...
Hello Jordi,

Check if the sheet that get the entry is not protected
(Tools|Protection).
If it is protected you may want to include this into your code
before
the
entry

Activesheet.Unprotect
...you code here
Activesheet.Protect

If it is has password you need to type the password after the
"Unprotect"
and "Protect".

Regards,

Jon-jon

"Jordi" wrote in message
...
If I exectue this simple code :

Range("F8").Select
ActiveCell.FormulaR1C1 = "=RC[-4]-RC[-2]"

It works great if I execute if from the current workbook but if
the
code
is
in another workbook and I include:
Windows("Libro1").Activate

It raises error 1004

Any help?