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#1
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Excel 2000 math question, repost
Steve,
Not too sure the exact details of what you want, but try =IF(L6775,(I67(L67),I67-(L67),0),0) -- HTH Bob Phillips ... looking out across Poole Harbour to the Purbecks (remove nothere from the email address if mailing direct) "Steve Lenaghan" wrote in message ... 1- I use a formula =IF(L6775,L67-75,0) to calculate extra billing charges in excess of 75 units. This works fine. 2- I have a second formula =IF(I67(L67),I67-(L67),0) to calculate charges, at a different rate, above the result of the first formula. This formula works fine if the result of formula 1 is 0, however if the result of formula 1 is 0 I get an undesirable figure. I've been playing with the formula but I haven't done this in 15 years and am lost. I have a attached a stripped version of sheet TIA Steve L. |
#2
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Excel 2000 math question, repost
Excel returns an error on formula
Steve L. "Bob Phillips" wrote in message ... Steve, Not too sure the exact details of what you want, but try =IF(L6775,(I67(L67),I67-(L67),0),0) -- HTH Bob Phillips ... looking out across Poole Harbour to the Purbecks (remove nothere from the email address if mailing direct) "Steve Lenaghan" wrote in message ... 1- I use a formula =IF(L6775,L67-75,0) to calculate extra billing charges in excess of 75 units. This works fine. 2- I have a second formula =IF(I67(L67),I67-(L67),0) to calculate charges, at a different rate, above the result of the first formula. This formula works fine if the result of formula 1 is 0, however if the result of formula 1 is 0 I get an undesirable figure. I've been playing with the formula but I haven't done this in 15 years and am lost. I have a attached a stripped version of sheet TIA Steve L. |
#3
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Excel 2000 math question, repost
Steve,
Sorry, I missed an IF. Try this instead =IF(L6775,IF(I67L67,I67-L67,0),0) -- HTH Bob Phillips ... looking out across Poole Harbour to the Purbecks (remove nothere from the email address if mailing direct) "Steve Lenaghan" wrote in message ... Excel returns an error on formula Steve L. "Bob Phillips" wrote in message ... Steve, Not too sure the exact details of what you want, but try =IF(L6775,(I67(L67),I67-(L67),0),0) -- HTH Bob Phillips ... looking out across Poole Harbour to the Purbecks (remove nothere from the email address if mailing direct) "Steve Lenaghan" wrote in message ... 1- I use a formula =IF(L6775,L67-75,0) to calculate extra billing charges in excess of 75 units. This works fine. 2- I have a second formula =IF(I67(L67),I67-(L67),0) to calculate charges, at a different rate, above the result of the first formula. This formula works fine if the result of formula 1 is 0, however if the result of formula 1 is 0 I get an undesirable figure. I've been playing with the formula but I haven't done this in 15 years and am lost. I have a attached a stripped version of sheet TIA Steve L. |
#4
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Excel 2000 math question, repost
That works fine as long as L75, however if L<75 the
formula returns a zero. but we are getting closer. Thanks so far... Steve L. "Bob Phillips" wrote in message ... Steve, Sorry, I missed an IF. Try this instead =IF(L6775,IF(I67L67,I67-L67,0),0) -- HTH Bob Phillips ... looking out across Poole Harbour to the Purbecks (remove nothere from the email address if mailing direct) "Steve Lenaghan" wrote in message ... Excel returns an error on formula Steve L. "Bob Phillips" wrote in message ... Steve, Not too sure the exact details of what you want, but try =IF(L6775,(I67(L67),I67-(L67),0),0) -- HTH Bob Phillips ... looking out across Poole Harbour to the Purbecks (remove nothere from the email address if mailing direct) "Steve Lenaghan" wrote in message ... 1- I use a formula =IF(L6775,L67-75,0) to calculate extra billing charges in excess of 75 units. This works fine. 2- I have a second formula =IF(I67(L67),I67-(L67),0) to calculate charges, at a different rate, above the result of the first formula. This formula works fine if the result of formula 1 is 0, however if the result of formula 1 is 0 I get an undesirable figure. I've been playing with the formula but I haven't done this in 15 years and am lost. I have a attached a stripped version of sheet TIA Steve L. |
#5
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Excel 2000 math question, repost
Steve,
Yes, I wondered about that. What do you want if L <75, or even if L = 75? -- HTH Bob Phillips ... looking out across Poole Harbour to the Purbecks (remove nothere from the email address if mailing direct) "Steve Lenaghan" wrote in message ... That works fine as long as L75, however if L<75 the formula returns a zero. but we are getting closer. Thanks so far... Steve L. "Bob Phillips" wrote in message ... Steve, Sorry, I missed an IF. Try this instead =IF(L6775,IF(I67L67,I67-L67,0),0) -- HTH Bob Phillips ... looking out across Poole Harbour to the Purbecks (remove nothere from the email address if mailing direct) "Steve Lenaghan" wrote in message ... Excel returns an error on formula Steve L. "Bob Phillips" wrote in message ... Steve, Not too sure the exact details of what you want, but try =IF(L6775,(I67(L67),I67-(L67),0),0) -- HTH Bob Phillips ... looking out across Poole Harbour to the Purbecks (remove nothere from the email address if mailing direct) "Steve Lenaghan" wrote in message ... 1- I use a formula =IF(L6775,L67-75,0) to calculate extra billing charges in excess of 75 units. This works fine. 2- I have a second formula =IF(I67(L67),I67-(L67),0) to calculate charges, at a different rate, above the result of the first formula. This formula works fine if the result of formula 1 is 0, however if the result of formula 1 is 0 I get an undesirable figure. I've been playing with the formula but I haven't done this in 15 years and am lost. I have a attached a stripped version of sheet TIA Steve L. |
#6
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Excel 2000 math question, repost
That was actually the simplest part of the whole thing.
If L =0 then the formula should calculate I - L -75 If L <=75 then the formula should calculate I - L 75 being the customer call allowance. I am not very good at nested calculations like this, can you suggest a good help source? Steve L. "Bob Phillips" wrote in message ... Steve, Yes, I wondered about that. What do you want if L <75, or even if L = 75? -- HTH Bob Phillips ... looking out across Poole Harbour to the Purbecks (remove nothere from the email address if mailing direct) "Steve Lenaghan" wrote in message ... That works fine as long as L75, however if L<75 the formula returns a zero. but we are getting closer. Thanks so far... Steve L. "Bob Phillips" wrote in message ... Steve, Sorry, I missed an IF. Try this instead =IF(L6775,IF(I67L67,I67-L67,0),0) -- HTH Bob Phillips ... looking out across Poole Harbour to the Purbecks (remove nothere from the email address if mailing direct) "Steve Lenaghan" wrote in message ... Excel returns an error on formula Steve L. "Bob Phillips" wrote in message ... Steve, Not too sure the exact details of what you want, but try =IF(L6775,(I67(L67),I67-(L67),0),0) -- HTH Bob Phillips ... looking out across Poole Harbour to the Purbecks (remove nothere from the email address if mailing direct) "Steve Lenaghan" wrote in message ... 1- I use a formula =IF(L6775,L67-75,0) to calculate extra billing charges in excess of 75 units. This works fine. 2- I have a second formula =IF(I67(L67),I67-(L67),0) to calculate charges, at a different rate, above the result of the first formula. This formula works fine if the result of formula 1 is 0, however if the result of formula 1 is 0 I get an undesirable figure. I've been playing with the formula but I haven't done this in 15 years and am lost. I have a attached a stripped version of sheet TIA Steve L. |
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