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Default Checking the last character is in a list

I'm probably staring at the answer here, but can't get it yet.

What I anm trying to do is go through a list of street numbers, and if
the last character is between A to F then copy that character to the
cell to the right of it, otherwise, leave it alone.

So far I've done this:

Sub SplitFlat()
Dim rgSheet As Range
Dim i As Integer
Dim stContents As String


Set rgSheet = Range("Properties")
For i = 1 To rgSheet.Rows.Count
stContents = rgSheet.Cells(i, 1).Value
If Right(stContents, 1) = "A" Then
rgSheet.Cells(i, 2).Value = Right(stContents, 1)
Else
rgSheet.Cells(i, 2).Value = Null
End If
Next i

End Sub

I thought I would be able to do

If Right(stContents, 1) between "A" to "F" Then ....

but it doesn't like that for some reason.

Would I be better using a case statement to do this, or will I have to
put the 6 possible values into an array, and check them against that?

I have always done this using a formula, but I want to try and learn
VBA, and examples like this tend to stick in my mind better than
following a book.

Cheers

Andrew H
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Default Checking the last character is in a list

You're welcome. If you're caught in such a nasty mess in the future,
consider preceding such a line with
s$ = Right(stContents, 1)
if efficiency matters.

You still can do better than that long ugly statement even when the
letters are not fully contiguous (exactly A through F). You could put
each valid letter in a range, like
A
C
D
F

and do a isna(vlookup) - or even better, do a more efficient match<0.
But you'd probably like using CHOOSE best of all - I'll let you
experiment with it.

But like you I'd have preferred something like "BETWEEN" or SQL's "IN"
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