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dim myStrings(1 to 3, 1 to 7) as string (this would result in a 3x7 array (21 elements)) Zone wrote: I want to set up, for lack of a better term, an array of strings, evidently a 2-D String array. The number of strings and the number of characters per string will vary according to conditions. How do I dimension the array? Thanks, James -- Dave Peterson |
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