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My bad ... I figured it out.
Thanks again! -- Krista "Krista" wrote: Yes, that's what I mean -- thanks. I tried this formula; however, nothing is appearing. I initially thought that's what the formula should be; however, it's not calculating ... the field is blank. Thanks. -- Krista "SteveG" wrote: Krista, Do you mean if the first 3 characters are "12x" or first 2 are "6x"? Try, =IF(E33="","",IF(LEFT(E33,3)="12x",F33*0.7*0.8,IF( LEFT(E33,2)="6x",F33*0.7*0.5,0))) HTH Steve -- SteveG ------------------------------------------------------------------------ SteveG's Profile: http://www.excelforum.com/member.php...fo&userid=7571 View this thread: http://www.excelforum.com/showthread...hreadid=552424 |
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