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![]() I have two graphs in excel. One graph has the values (1,3), (3,5), (5, 9), (7, 13) etc. The second graph has the values (2,3), (4,7), (6, 11), (8, 19) etc. I would like to draw a third graph using the two graphs like (1, y1/y2), (2, y1/y2), (3, y1/y2), (4, y1/y2) etc. Here y1 is the value from graph 1 and y2 the corresponding value from graph 2. Now, I am doing using a long method. First find the equation for graph 1 and then find the y values for x=1,2,3 etc. The technique is repeated for graph 2. Then I divide the values and plot the graph. It is tedious. Is there a faster way? -- labview1958 ------------------------------------------------------------------------ labview1958's Profile: http://www.excelforum.com/member.php...o&userid=32123 View this thread: http://www.excelforum.com/showthread...hreadid=542878 |
#2
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![]() Anyone can help? -- labview1958 ------------------------------------------------------------------------ labview1958's Profile: http://www.excelforum.com/member.php...o&userid=32123 View this thread: http://www.excelforum.com/showthread...hreadid=542878 |
#3
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![]() anyone can offer any help? -- labview1958 ------------------------------------------------------------------------ labview1958's Profile: http://www.excelforum.com/member.php...o&userid=32123 View this thread: http://www.excelforum.com/showthread...hreadid=542878 |
#4
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![]() Anyone out there can help? -- labview1958 ------------------------------------------------------------------------ labview1958's Profile: http://www.excelforum.com/member.php...o&userid=32123 View this thread: http://www.excelforum.com/showthread...hreadid=542878 |
#5
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You feel like explaining what you want?
- Jon ------- Jon Peltier, Microsoft Excel MVP Tutorials and Custom Solutions http://PeltierTech.com _______ "labview1958" wrote in message ... Anyone out there can help? -- labview1958 ------------------------------------------------------------------------ labview1958's Profile: http://www.excelforum.com/member.php...o&userid=32123 View this thread: http://www.excelforum.com/showthread...hreadid=542878 |
#6
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![]() Graph 1.(measurement) (1,3), (3,5), (5, 9), (7, 13) Graph 2.(measurement) (2,3), (4,7), (6, 11), (8, 19) Graph 3.(calculation) (1, y1/y2), (2, y1/y2), (3, y1/y2), (4, y1/y2) where y1 and y2 is obtained by first drawing a trendline, finding it's equation and then substituting the x value to find the corresponding y value. The two y values corresponding to a particular x is then found. The ratio of the two y values is then calculated. Finally a third graph is drawn. The whole process is tedious. Is there a simpler way? -- labview1958 ------------------------------------------------------------------------ labview1958's Profile: http://www.excelforum.com/member.php...o&userid=32123 View this thread: http://www.excelforum.com/showthread...hreadid=542878 |
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