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#1
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Please help with Time calculations
I need to calculate in a cell the time duration when the user inters start
and end times in the following fashion: Start End Duration 00:00 00:45 0.75 00:45 01:30 0.75 Start and End times must be in 24hr format. My problem is in the duration. I am required to calculate the duration like the example above i.e. instead of showing it as 0:45 min (00:00 (12:00 AM) €“ 00:45 (12:45 AM) = 0:45 minutes, my client requires it to show as three quarters of an hour in decimal format (0.75). how can I do that? I need the user to enter 00:00 and 00:45 then the form will calculate the 0.75. Thanks Al |
#2
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Hi!
=(B1-A1)*24 Format as GENERAL Biff "Al" wrote in message ... I need to calculate in a cell the time duration when the user inters start and end times in the following fashion: Start End Duration 00:00 00:45 0.75 00:45 01:30 0.75 Start and End times must be in 24hr format. My problem is in the duration. I am required to calculate the duration like the example above i.e. instead of showing it as 0:45 min (00:00 (12:00 AM) - 00:45 (12:45 AM) = 0:45 minutes, my client requires it to show as three quarters of an hour in decimal format (0.75). how can I do that? I need the user to enter 00:00 and 00:45 then the form will calculate the 0.75. Thanks Al |
#3
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Time is a fraction of 1 day, so just multiply by 24. For example
=(B2-A2)*24 and format as general. -- HTH RP (remove nothere from the email address if mailing direct) "Al" wrote in message ... I need to calculate in a cell the time duration when the user inters start and end times in the following fashion: Start End Duration 00:00 00:45 0.75 00:45 01:30 0.75 Start and End times must be in 24hr format. My problem is in the duration. I am required to calculate the duration like the example above i.e. instead of showing it as 0:45 min (00:00 (12:00 AM) - 00:45 (12:45 AM) = 0:45 minutes, my client requires it to show as three quarters of an hour in decimal format (0.75). how can I do that? I need the user to enter 00:00 and 00:45 then the form will calculate the 0.75. Thanks Al |
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