My last message had the wrong opening sentence (it was meant for another
message I was working on). This is what I meant to post...

The function I posted does not work as I had indicated... it finds the last
7-digit number, not the first. Here is the corrected code (plus I added the
missing *MISSING* indicator)...

Function First7DigitNumber(S As String) As String
Dim X As Long
For X = 1 To Len(S)
If Mid(" " & S & " ", X, 9) Like "[!0-9]#######[!0-9]" Then
First7DigitNumber = Mid(S, X, 7)
Exit Function
End If
Next
First7DigitNumber = "*MISSING*"
End Function

--
Rick (MVP - Excel)


"Rick Rothstein" wrote in message
...
I am still not sure if the OP wanted the 7-digit number to stand alone (as
a "word") or not, so I just went for the first isolated 7 digits in a
row...

Function First7DigitNumber(S As String) As String
Dim X As Long
For X = 1 To Len(S)
If Mid(" " & S & " ", X, 9) Like "[!0-9]#######[!0-9]" Then
First7DigitNumber = Mid(S, X, 7)
Exit Function
End If
Next
First7DigitNumber = "*MISSING*"
End Function

--
Rick (MVP - Excel)


"Ron Rosenfeld" wrote in message
...
On Sat, 18 Jul 2009 10:54:43 -0400, "Rick Rothstein"
wrote:

Function First7DigitNumber(S As String) As String
Dim X As Long
For X = 1 To Len(S)
If Mid(" " & S & " ", X, 9) Like "[!0-9]#######[!0-9]" Then
First7DigitNumber = Mid(S, X, 7)
End If
Next
End Function

I note that given the following modification of the OP's test string:

"User requested authority of emergency ID for reason NHUSER1234567
Restore
of object to library LEVEL2 under remedy 61074317. 06/04/09 17:46 QPGMR"

your routine returns 1234567 whereas my UDF returns "MISSING" since
there are
no seven digit words.

(Lori's formulas return 1074317)

--ron