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In that case you should change the 1000 in all four places to
something that is bigger than the maximum number of alarm types/rows. On Tue, 5 Aug 2008 07:55:00 -0700, computers hate me wrote: because right now there are only 700 but we will add more eventually and it could add up to about 2000. So i wanted to set the formula so that if we add more it will still work "Lars-Åke Aspelin" wrote: Also, this formula relies on that the range with alamrs is less than 1000 rows. You said that you have 700 alarms, so why do you enter A$2:A$2000 ?? On Tue, 05 Aug 2008 14:20:01 GMT, Lars-Åke Aspelin wrote: Did you enter the formula as an array formula? If you don't do that, you will get NUM# error. Lars-Åke On Tue, 5 Aug 2008 07:03:02 -0700, computers hate me wrote: ok it gives me a NUM# Error I dont understand the formula so i dont know how to subtitute my values into it this is the formula i used =INDEX('Bf 4 Alarms'!A$2:A$2000,MATCH(INDEX('Bf 4 Alarms'!D$2:D$2000+ROW(A$2:A$2000)/1000, MATCH(LARGE('Bf 4 Alarms'!D$2:D$2000+ROW(A$2:A$2000)/1000,ROW()),'Bf 4 Alarms'!D$2:D$2000+ROW(A$2:A$2000)/1000,0)),'Bf 4 Alarms'!D$2:D$2000+ROW(A$2:A$2000)/1000,0)) "Lars-Åke Aspelin" wrote: On Tue, 5 Aug 2008 05:36:01 -0700, Bertha needs help wrote: I have a list of 700 alarms in column A then In column B i have a formula that counts how many times each alarm went off. In another sheet i want to make a chart that shows the top 10 alarms that went off that day. What formula could i use to find the top 10 values? In cell A1 of the other sheet, put =INDEX(Sheetq!A$1:A$700,MATCH(INDEX(Sheet1!B$1:B$7 00+ROW(A$1:A$700)/1000, MATCH(LARGE(Sheet1!B$1:B$700+ROW(A$1:A$700)/1000,ROW()), Sheet1!B$1:B$700+ROW(A$1:A$700)/1000,0)),Sheet1!B$1:B$700+ROW(A$1:A$700)/1000,0)) Note this formula is an array formula that has to be entered by CTRL+SHIFT+ENTER rather than just ENTER. In cell B1 of the other sheet, put =LARGE(Sheet1!B$1:B$700,ROW()) Copy these formulas from A1:B1 down to A10:B10 to get the table of the names of the 10 most frequent alarms and their respective frequencies. Hope this helps / Lars-Åke |
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