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Well, Chris, I hope you are suitably invigorated now to face the next
challenges - thanks for feeding back. Pete "Chris" wrote in message ... Thanks Pete, that worked brilliantly. After 2 days of slogging on it I had given up hope and lost the will to live! Thanks Chris "Pete_UK" wrote: No, that's fine. COUNT(range) will count all the cells which are not empty and which contain numbers, so that represents the maximum attendances expected. COUNTIF can be used to count only the cells containing a particular value (1), so you can put these together to get a percentage: =COUNTIF(range,1)/COUNT(range) and format the cell as a percentage. Here "range" will be something like B2:AM2 for the first student in row 2, and then you can copy this down for the other students. Hope this helps. Pete "Chris" wrote in message ... Thanks Pete. I was hoping to use Y and A but having already had some problems with using a letter (with autocorrect that affected the whole suite!) I was hoping to just use a 1 for attending and 0 for non attendance. The 7th attendance, if not needed, would be blank. If that would create yet more problems maybe you have a suggestion? Chris "Pete_UK" wrote: How do you indicate in column A that it should be 6 or 7 attendances for each student? Is your attendance shown as Y and absence shown as A, or do you have some other codes? Do you leave the column blank for a student who is not expected to be in (on the 7th session)? Please give a few more details. Pete "Chris" wrote in message ... Me again! Some of our students have to attend 6 times and some 7. They are listed down column A with various details (including attendance) running across the row. At the end of all of their attendance days is a 'total attendance'column. Assuming they all attend all of the days (I wish!!) is there a one formula fits all solution to show the percentage of attendance for each student. If they do attend 6 or 7 (as required) it will still amount to 100%. I could then copy that formula down all of the students and this would save separate formulae for each of the 6's and 7's. A nightmare to sort out! Thanks |
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