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Countif indirect question
=COUNTIF(A1:A5,""&B1)
On Aug 8, 12:39 pm, "PCLIVE" wrote: Without the "--", the results of matching the items in A1:A5 will be either True or False in which case the final result is "0". Using "--" converts the True and False to ones (1) or zeros (0). SUMPRODUCT is normally useful to get a count of items that match certain, multiple criteria from the same row or even multiple rows. Though the SUMPRODUCT formula gives the correct answer, I think the COUNTIF formula provided by Toppers is way to go. Toppers, I thought I had tried the COUNTIF formula the way you did and it returned an error. Obviously I was mistaken as it works now. Thanks. -- "Doug Laidlaw" wrote in message ... Yes! I was trying every option under the sun by moving the quotation marks " . I knew it was a simple but I couldn't get it. PCLIVE earlier helped me with the =SUMPRODUCT(--(A1:A5B1)). What is the -- part of the formula doing? Your answer works, but I don't know how! Thank you both, Doug "Toppers" wrote: =countif(A1:A5,"" & B1) "PCLIVE" wrote: I would have expected something like that to work too, but it doesn't for me. Instead, try: =SUMPRODUCT(--(A1:A5B1)) HTH, Paul -- "Sean Timmons" wrote in message ... =countif(A1:A5,B1) "Doug Laidlaw" wrote: As an example I have numerical data in cells A1:A5 (12,0,1,7,2). In cell B1 I have the number 3. Now in cell A6 I want to count the number of cells that are greater than 3. The answer should be 2. The countif formula lets me put =countif(A1:A5,3) but I want to have linked it cell B1 so I can change the parameter. I am trying to do this with the Indirect function but I can not figure it out. Thanks!- Hide quoted text - - Show quoted text - |
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