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Confining a point in a rectangle
Hi,
This problem involves more of algebra and geometry. I rely on excel to perform some calculations. I have two parallel slopes (+'ive) and two slopes which is perpendicular to these two slopes (-'ive). This design makes a rectangle and I have a point (x,y). My objective is to come up with conditions which will check whether a point is within this rectangle or not and assign a value. In my current design, I have two positive slopes A and B that are parallel and have different y-intercepts (slope A at the bottom and slope B and the top). I have two negative slopes C and D that are perpendicular to A and B and also have different y-intercepts (slope D at the bottom and slope C at the top) . This makes a rectangle. The conditions that I have come up with is: m - slope and c - intercept A slope - yma(x)+ca B slope - y<mb(x)+cb C slope - y<mc(x)+cc D slope - ymd(x)+cd I have noticed that this conditon only works for 0 to 90 degrees. But if i happen to shift my rectange to another angle beyond 90 degrees and apply the same thing to 90-180, or 180-270 or 270-360 degrees, it doesnt work. Can anyone suggest any solution to my logic. Thanks |
#2
Posted to microsoft.public.excel.misc
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Confining a point in a rectangle
In almost every computer solution dealing with such things, I've had to treat
the 4 cardinal points (0, 90, 180, 270) as unique exceptions and specifically test for them. In some cases (depending on the application) when such an angle was encountered, then an intentional error of some small fraction of a degree can be introduced to prevent the failure. In some applications this is acceptable, in others it is not. " wrote: Hi, This problem involves more of algebra and geometry. I rely on excel to perform some calculations. I have two parallel slopes (+'ive) and two slopes which is perpendicular to these two slopes (-'ive). This design makes a rectangle and I have a point (x,y). My objective is to come up with conditions which will check whether a point is within this rectangle or not and assign a value. In my current design, I have two positive slopes A and B that are parallel and have different y-intercepts (slope A at the bottom and slope B and the top). I have two negative slopes C and D that are perpendicular to A and B and also have different y-intercepts (slope D at the bottom and slope C at the top) . This makes a rectangle. The conditions that I have come up with is: m - slope and c - intercept A slope - yma(x)+ca B slope - y<mb(x)+cb C slope - y<mc(x)+cc D slope - ymd(x)+cd I have noticed that this conditon only works for 0 to 90 degrees. But if i happen to shift my rectange to another angle beyond 90 degrees and apply the same thing to 90-180, or 180-270 or 270-360 degrees, it doesnt work. Can anyone suggest any solution to my logic. Thanks |
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