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#1
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Count duplicates once
I need to count how many different codes/numbers are in a list, and some of
them are duplicated. eg: 300001600 300001600 300002465 300001435 300005642 I need the result to show that there are 4 different numbers, rather than 5 in total. |
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#2
Posted to microsoft.public.excel.misc
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Count duplicates once
If the codes/numbers are strictly numbers:
=COUNT(1/FREQUENCY(A1:A10,A1:A10)) If they may be alphanumeric: =SUMPRODUCT((A1:A10<"")/COUNTIF(A1:A10,A1:A10&"")) Biff "Tinkerbell1178" wrote in message ... I need to count how many different codes/numbers are in a list, and some of them are duplicated. eg: 300001600 300001600 300002465 300001435 300005642 I need the result to show that there are 4 different numbers, rather than 5 in total. |
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#3
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hello,
i have the same problem. I used the formula you suggested but it only works if the data series is predefined. i have a column of data to count and they change from month to month. I tried =SUMPRODUCT((A:A<"")/COUNTIF(A:A,A:A&"")) but it doesn't work. Any suggestions? |
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