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JE,
Right, I now saw what went wrong. I also noticed that it is not necessary to array enter. How should the formula be modified if it must work for al larger range than only the cells with the correct entries. I tried to put in A2:F3 in stead of A2:F2 but then it says FALSE. Why? You wrote "COUNT() counts the number of numeric values returned and ignores the #N/A errors", so if all the correct values are allready in A2:F2 why has the formula problems with other cells? What I am looking for is a formula that shows TRUE if in the used range each element of the {.....} part is found at least once. I tried =COUNT(MATCH({2,5,234,"a",-10,"dce"},A2:F3,0))=6 with A3:F3 blank but to no avail. It seems that MATCH() returns 6 times #N/A for the A3:F3 part of the range and nothing for the A2:F2 part. Please help me out again. Jack. "JE McGimpsey" schreef in bericht ... Substituting your array in place of ROW(INDIRECT("1:6")) and array-entering the result works fine for me: =COUNT(MATCH({2,5,234,"a",-10,"dce"},A2:F2,0))=6 In article , "Jack Sons" wrote: What if the 6 elements of the range A2:F2 are not the neat 1 to 6 but, say, 2, 5, 234, a, -10 and dce? Must {2,5,234,"a",-10,"dce"} be put in the place of ROW(INDIRECT("1:6"))? I tried, I entered and array entered, but the formula in both cases results in zero. Please help me further. |
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