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#1
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Why doesn't the equation correspond to the graphic?
Hi.
I drew a graph using some data. So I asked Excel to put the tendency curve using a 5th degree polinomial. I also asked for the equation. The problem is when I input the points into the equation the y values do not correspond to the ones in the graph. Can you help me? If necessary I can send you the file with the data. Thanks. |
#2
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Why doesn't the equation correspond to the graphic?
The trend line equations displayed in Excel normally do not have sufficient
significant places to be used directly in an equation. Select the trend line equation on the chart and change the format such that there are more significant places. (This has burnt me in the past, I always check by plotting the calculated values on the chart with the trend line showing to insure I amm close enough.) "Ismael Jr" wrote: Hi. I drew a graph using some data. So I asked Excel to put the tendency curve using a 5th degree polinomial. I also asked for the equation. The problem is when I input the points into the equation the y values do not correspond to the ones in the graph. Can you help me? If necessary I can send you the file with the data. Thanks. |
#3
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Why doesn't the equation correspond to the graphic?
Hi, BJ.
Thanks for your fast answer. The points a I don't know hoe to change number of places for the coefficients. Besides, the difference is big. It's not a matter of rounding. For example, in the graph the value is 8.4 and the equation gives 11.0. Do you think is only a matter of places? So, how can I change this? Thanks a lot "bj" wrote: The trend line equations displayed in Excel normally do not have sufficient significant places to be used directly in an equation. Select the trend line equation on the chart and change the format such that there are more significant places. (This has burnt me in the past, I always check by plotting the calculated values on the chart with the trend line showing to insure I amm close enough.) "Ismael Jr" wrote: Hi. I drew a graph using some data. So I asked Excel to put the tendency curve using a 5th degree polinomial. I also asked for the equation. The problem is when I input the points into the equation the y values do not correspond to the ones in the graph. Can you help me? If necessary I can send you the file with the data. Thanks. |
#4
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Why doesn't the equation correspond to the graphic?
look on the toolbars for a button that looks something like
.0 ..00 or select the trend line equation <format<selected data labels<number and change the number in the decimal Places box the 11 vs 8.4 is exactly the type of problem I had a difference in significant figures will easily give this type of difference "Ismael Jr" wrote: Hi, BJ. Thanks for your fast answer. The points a I don't know hoe to change number of places for the coefficients. Besides, the difference is big. It's not a matter of rounding. For example, in the graph the value is 8.4 and the equation gives 11.0. Do you think is only a matter of places? So, how can I change this? Thanks a lot "bj" wrote: The trend line equations displayed in Excel normally do not have sufficient significant places to be used directly in an equation. Select the trend line equation on the chart and change the format such that there are more significant places. (This has burnt me in the past, I always check by plotting the calculated values on the chart with the trend line showing to insure I amm close enough.) "Ismael Jr" wrote: Hi. I drew a graph using some data. So I asked Excel to put the tendency curve using a 5th degree polinomial. I also asked for the equation. The problem is when I input the points into the equation the y values do not correspond to the ones in the graph. Can you help me? If necessary I can send you the file with the data. Thanks. |
#5
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Why doesn't the equation correspond to the graphic?
BJ
You are right!! When I increased 1 place the result got much better. Thanks a lot!! "bj" wrote: look on the toolbars for a button that looks something like .0 .00 or select the trend line equation <format<selected data labels<number and change the number in the decimal Places box the 11 vs 8.4 is exactly the type of problem I had a difference in significant figures will easily give this type of difference "Ismael Jr" wrote: Hi, BJ. Thanks for your fast answer. The points a I don't know hoe to change number of places for the coefficients. Besides, the difference is big. It's not a matter of rounding. For example, in the graph the value is 8.4 and the equation gives 11.0. Do you think is only a matter of places? So, how can I change this? Thanks a lot "bj" wrote: The trend line equations displayed in Excel normally do not have sufficient significant places to be used directly in an equation. Select the trend line equation on the chart and change the format such that there are more significant places. (This has burnt me in the past, I always check by plotting the calculated values on the chart with the trend line showing to insure I amm close enough.) "Ismael Jr" wrote: Hi. I drew a graph using some data. So I asked Excel to put the tendency curve using a 5th degree polinomial. I also asked for the equation. The problem is when I input the points into the equation the y values do not correspond to the ones in the graph. Can you help me? If necessary I can send you the file with the data. Thanks. |
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