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#1
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I'm having trouble creating a formula to tell me an accurate tank volume in a tank when it is tilted.
I know the following: Step 1: Tank Capacity Tank Diameter:96 inch Tank Length: 256 inch So total capacity is : 8021.59 Gallons Formula [=(("Diameter"/2)*("Diameter"/2)*PI()*"Tank Length")/231] Step 2: Tank Volume measurement using a dipstick Striker plate: .25 inch Stick Reading:78.75 inch Volume in Tank:7,062.54 Gallons Formula [="Tank Length"*((("Diameter"/2)^2*(ACOS((("Diameter"/2)-("Stick Reading"+"Striker plate"))/("Diameter"/2))))-(SQRT(2*(("Diameter"/2)*("Stick Reading"+"Striker plate"))-("Stick Reading"+"Striker plate")^2)*(("Diameter"/2)-("Stick Reading"+"Striker plate"))))/231] Step 3: Tank Tilt Fill point 1: 78.75 inch Fill point 2: 75 inch Distance between to two fill point: 198 inch Difference is: 78.75(in)-75(in) = 3.75(in) The ratio is: 256(in)/ 198(in) = 1.29(in) So the tank tilt is: 1.29(in) * 3.75(in) = 4.85(in) So I know the Tank Tilt, but what formula should I use to find out how much volume is in the tank when measuring from fill point 1 only. I'm sure it is more than the 7,062.54 Gallons from step 2. Last edited by Harlemshake : March 2nd 13 at 03:24 PM |
#2
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Posted to microsoft.public.excel.charting
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On Fri, 22 Feb 2013 21:47:08 +0000, Harlemshake
wrote: I'm having trouble creating a formula to tell me an accurate tank volume in a tank when it is tilted. I know the following: Step 1: Tank Capacity Tank Diameter:96 inch Tank Length: 256 inch So total capacity is : 8021.59 Gallons Formula {=(("Diameter"/2)*("Diameter"/2)*PI()*"Tank Length")/231] Step 2: Tank Volume measurement using a dipstick Striker plate: .25 inch Stick Reading:78.75 inch Volume in Tank:3,854.11 Gallons Formula [="Tank Length"*((("Diameter"/2)^2*(ACOS((("Diameter"/2)-("Stick Reading"+"Striker plate"))/("Diameter"/2))))-(SQRT(2*(("Diameter"/2)*("Stick Reading"+"Striker plate"))-("Stick Reading"+"Striker plate")^2)*(("Diameter"/2))))/231] Step 3: Tank Tilt Fill point 1: 78.75 inch Fill point 2: 75 inch Distance between to two fill point: 198 inch Difference is: 78.75(in)-75(in) = 3.75(in) The ratio is: 256(in)/ 198(in) = 1.29(in) So the tank tilt is: 1.29(in) * 3.75(in) = 4.85(in) So I know the Tank Tilt, but what formula should I use to find out how much volume is in the tank when measuring from fill point 1 only. I'm sure it is more than the 3,854.11 Gallons from step 2. In a perfectly round cylinder, the vertical fill level remains in place as the tank is tilted, and only the end points rise and fall against the tank walls. Without considering meniscus offset from surface tension, that fill level point will always be the halfway point between the two crests in the ellipsoid created by the tipping. So, if you have one dimension, you have the other, and you can find the actual fill level dimension at the center between those two points. That center from the bottom of the cylinder is the fill measure. |
#3
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Thanks for the help but I was able to build the spread sheet with the formula from this link http://planetcalc.com/1442/
Thanks again. https://docs.google.com/file/d/0Bx6_...it?usp=sharing Last edited by Harlemshake : March 2nd 13 at 04:10 PM |
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