Fuel Tank Tilt vloume from fuel point in Gallons
On Fri, 22 Feb 2013 21:47:08 +0000, Harlemshake
wrote:
I'm having trouble creating a formula to tell me an accurate tank volume
in a tank when it is tilted.
I know the following:
Step 1: Tank Capacity
Tank Diameter:96 inch
Tank Length: 256 inch
So total capacity is : 8021.59 Gallons
Formula {=(("Diameter"/2)*("Diameter"/2)*PI()*"Tank Length")/231]
Step 2: Tank Volume measurement using a dipstick
Striker plate: .25 inch
Stick Reading:78.75 inch
Volume in Tank:3,854.11 Gallons
Formula [="Tank Length"*((("Diameter"/2)^2*(ACOS((("Diameter"/2)-("Stick
Reading"+"Striker
plate"))/("Diameter"/2))))-(SQRT(2*(("Diameter"/2)*("Stick
Reading"+"Striker plate"))-("Stick Reading"+"Striker
plate")^2)*(("Diameter"/2))))/231]
Step 3: Tank Tilt
Fill point 1: 78.75 inch
Fill point 2: 75 inch
Distance between to two fill point: 198 inch
Difference is: 78.75(in)-75(in) = 3.75(in)
The ratio is: 256(in)/ 198(in) = 1.29(in)
So the tank tilt is: 1.29(in) * 3.75(in) = 4.85(in)
So I know the Tank Tilt, but what formula should I use to find out how
much volume is in the tank when measuring from fill point 1 only. I'm
sure it is more than the 3,854.11 Gallons from step 2.
In a perfectly round cylinder, the vertical fill level remains in place
as the tank is tilted, and only the end points rise and fall against the
tank walls.
Without considering meniscus offset from surface tension, that fill
level point will always be the halfway point between the two crests in
the ellipsoid created by the tipping.
So, if you have one dimension, you have the other, and you can find the
actual fill level dimension at the center between those two points. That
center from the bottom of the cylinder is the fill measure.
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