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How do I solve for x in a second-order polynomial trend?
I have instrument calibration data that is best characterized as quadratic- I
need to back-calculate for an adjusted point, using the basic formula y= ax^2 + bx + c. I'm horrible at formulae in excel! |
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#2
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How do I solve for x in a second-order polynomial trend?
You could use Goal Seek to find X, given Y, or you could use the standard
quadratic equation solution (-B +/- SQRT(B^2-4*A*C))/(2*A) -- David Biddulph "DianeD" wrote in message ... I have instrument calibration data that is best characterized as quadratic- I need to back-calculate for an adjusted point, using the basic formula y= ax^2 + bx + c. I'm horrible at formulae in excel! |
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#3
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How do I solve for x in a second-order polynomial trend?
Thank you!! Dyslexic chemists and excel don't always play well together :-)
"David Biddulph" wrote: You could use Goal Seek to find X, given Y, or you could use the standard quadratic equation solution (-B +/- SQRT(B^2-4*A*C))/(2*A) -- David Biddulph "DianeD" wrote in message ... I have instrument calibration data that is best characterized as quadratic- I need to back-calculate for an adjusted point, using the basic formula y= ax^2 + bx + c. I'm horrible at formulae in excel! |
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