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DianeD

How do I solve for x in a second-order polynomial trend?
 
I have instrument calibration data that is best characterized as quadratic- I
need to back-calculate for an adjusted point, using the basic formula y= ax^2
+ bx + c.

I'm horrible at formulae in excel!

David Biddulph

How do I solve for x in a second-order polynomial trend?
 
You could use Goal Seek to find X, given Y, or you could use the standard
quadratic equation solution (-B +/- SQRT(B^2-4*A*C))/(2*A)
--
David Biddulph

"DianeD" wrote in message
...
I have instrument calibration data that is best characterized as quadratic-
I
need to back-calculate for an adjusted point, using the basic formula y=
ax^2
+ bx + c.

I'm horrible at formulae in excel!




DianeD

How do I solve for x in a second-order polynomial trend?
 
Thank you!! Dyslexic chemists and excel don't always play well together :-)

"David Biddulph" wrote:

You could use Goal Seek to find X, given Y, or you could use the standard
quadratic equation solution (-B +/- SQRT(B^2-4*A*C))/(2*A)
--
David Biddulph

"DianeD" wrote in message
...
I have instrument calibration data that is best characterized as quadratic-
I
need to back-calculate for an adjusted point, using the basic formula y=
ax^2
+ bx + c.

I'm horrible at formulae in excel!






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