{=AVERAGE(IF(A1:A5<MIN(A1:A5),A1:A5))}

would behave differently than

=(SUM(A1:A5)-MIN(A1:A5))/(COUNT(A1:A5)-1)

when, for example:

A1: 3
A2: 4
A3: 3
A4: 6
A5: 3

Bob Phillips wrote:
Not so much an interpretation as an alternative <ebg

Bob

"Dave Peterson" wrote in message
...

And one more interpretation <bg:
=(SUM(A1:A10)-MIN(A1:A10))/(COUNT(A1:A10)-1)



Bob Phillips wrote:

I am reading this not as the average subtract the lowest value, but as

the

average of all but the lowest value. If so, you can use

=AVERAGE(IF(A1:A5<MIN(A1:A5),A1:A5))

which is an array formula, so commit with Ctrl-Shift-Enter

--
HTH

Bob Phillips

"Mangesh Yadav" wrote in message
. ..

= AVERAGE(A1:A10)-MIN(A1:A10)

Mangesh



"ingersollg" wrote in message
...

I need the average of an array of values, minus the lowest value of

those

entries.


--

Dave Peterson