That should have worked.

But I think it does too much work as will slow down your workbook when it
recalculates.

Instead I'd dedicate as separate column that would return the number the
matching row:

Say in column B (cell b6???)
=match(a6,'[datasheet.xls]sheet1'!a:a,0)
Then drag this portion down the column as far as you need it.

Then you can use:
=index('[datasheet.xls]sheet1'!b:b,b6)
and
=index('[datasheet.xls]sheet1'!c:c,b6)
....

You may want to make sure that you did find a match.

=if(iserror(b6),"no match",index('[datasheet.xls]sheet1'!b:b,b6))
....

So the important part of your formula (the portion that looks for a match) is
only calculated one time.

PeteT. wrote:

I have a spreadsheet with about 50 columns and up to several hundred rows
with column A containing the Team Name.
I have a simple table setup with each of the team names on one tab of a
sheet...on the 2nd tab, I was trying to run a v-lookup to return up to the
first 50 of each team name along with the data from first 22 columns....

The formula is/was
=vlookup(TeamTableA!6,'[DataSheet.xls]Sheet1'!$A:$V,{1,2,3,etc up to
22},FALSE)

I figured the array {1,2,3} would return the first 22 columns in the
row....but apparently not..

I also only want to return up to the first 50 instances of each team name.
I can figure out how to make each unique if need be but any help on getting
the lookup to return the first 22 columns in the row would be appreciated.

--

Dave Peterson