Thread: "IF" formula
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Pete_UK Pete_UK is offline
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Default "IF" formula

Okay, I think this is what you want:

=IF(F316, F3*($I$2 + 1.35), F3*$I$2)

Hope ths helps.

Pete

On Nov 6, 1:07*pm, George wrote:
Thanks again Pete, it's close, but I don't want to multiply by the 1.35, I
want to add the 1.35 to the existing number. *The existing number is 4.75, if
the square footage is over 16 I want the new multiplier to be 6.10, (4.75 +
1.35) but if the square footage is under 16 I need the multiplier to remain
at 4.75



"Pete_UK" wrote:
Well then, try this:


=IF(F316, F3*$I$2*1.35, F3*$I$2)


using the same cell references as before.


Hope this helps.


Pete


On Nov 6, 12:43 pm, George wrote:
Thanks Pete, here is what I need;
I have one cell that has a square footage number in it, this number is then
multiplied by another number in a different cell. *If the square footage
number goes over 16, I would like to multipy the square footage number by the
original number plus 1.35 more.


"Pete_UK" wrote:
As you are not very specific, try this:


=IF(F3predetermined_number, F3*greater_number, F3*$I$2)


Hope this helps.


Pete


On Nov 5, 6:26 pm, George wrote:
I have a formula in a cell =sum(F3*$I$2), I would like to add another formula
that changes I2 to a greater number if F3 is greater then a predetermined
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