Cutoff score for acceptance
On Aug 12, 6:02*pm, wrote:
On Aug 12, 5:55*pm, Wigi wrote:
Hi
x is the unknown.
(x-500)/100 = -0.25
(x-500) = -25
(x-500) +500 = -25 + 500
x = -25 + 500
x = 475
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Wigihttp://www.wimgielis.be=Excel/VBA, soccer and music
" wrote:
Good afternoon, this is not a homework question, I am trying to brush
up on statistics for my job. I am having a problem with a question. A
4 year college will accept any student ranked in the top 60% on a
National Examination. If the test score is normally distributed with a
mean of 500 and a standard deviation of 100, what is the cutoff score
for acceptance?
The book says 475. If I take =NORMSINV(1-A1) where A1 houses 0.6 it
gives me -0.25 the z-score but how do I come up with 475? If I check
the equasion with the answer =(475-500)/100 it will give me -0.25. How
do I solve the unknown?
Thanks in advance
PJ- Hide quoted text -
- Show quoted text -
Pete_UK, Thank you so much! I just could not get it.- Hide quoted text -
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Wigi, thanks also.
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