Removing a period and leaving maintaingn a fixed #of numbers
Thank You
"Ron Coderre" wrote:
Try this:
=IF(COUNTIF(A10,"*@????-*"),TRIM(MID(A10,FIND("@",A10)+6,LEN(A10))),"")
Is that something you can work with?
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Regards,
Ron (XL2003, Win XP)
Microsoft MVP (Excel)
"Iguss" wrote in message
...
Hi,
One more question
Cell is empty
#VALUE!
Callable 12/15/07@101 (should be blank)
Callable - Sinking Fund 05/01/08@100 - Escrowed Escrowed
Callable 05/15/08@100 - Bank
Escrowed
=TRIM(MID(CallDate,FIND("@",CallDate)+6,LEN(CallDa te)))
Thank you for help
How do I get above results without the #value!
"Ron Coderre" wrote:
Try this:
=LEFT(SUBSTITUTE(A10,".",""),9)
Is that something you can work with?
--------------------------
Regards,
Ron (XL2003, Win XP)
Microsoft MVP (Excel)
"Iguss" wrote in message
...
Good Morning,
How Can I combine these two?
=substitute(a1,".","") and =left(a1,9)
I have a string of numbers and I have a period among those numbers(the
period is not in a fixed place), I would like to remove the period and
always
keep first left nine digits.
Lets say 42.254420115600000000, 422542011
Thank you for your help
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