Yeah, you're right David - maybe the post would have been better off
lost in the ether !!

Pete

On Oct 24, 7:46 am, "David Biddulph" <groups [at] biddulph.org.uk
wrote:
Answering too late at night, I think, Pete. :-)
What he needs (I believe) is just =MOD(A1,180), which gives 138 for his
example input of 678, whereas your formula gives 24840. :-(
--
David Biddulph

"Pete_UK" wrote in message

ups.com...



Assuming your numbers start in cell A1 and go down the column, put
this in B1:

=IF(A1<180,A1,ROUND(180*MOD(A1,180),0))

and copy the formula down for as many entries as you have in column A.
You can then fix the values produced by the formula by highlighting
column B, clicking <copy then Edit | Paste Special | Values (check) |
OK then <Enter. Now you will be able to delete column A, leaving you
with the range of values you want.

Hope this helps.

Pete

On Oct 23, 11:03 pm, "Tim R" wrote:
This one is way beyond me....I have a column with numbers varying from 12
or
30 to 800 or so...what I am trying to due is check the column cells for
the
number...if the number is greater than 180 then I need to reduce the
number
to an integer that is the 'remainder' of the number divided by 180

Or in figures ....cell number is greater than 180 = 678 / 180 = 3.766

now I need to get rid of the 3 and just enter the value of 180 times
.766%
= 138 (rounded off)

The whole number 138 is what I need as the result

Again...this is only if the original cell value is greater than
180...179,
32, etc are to be left alone

Thanks, Tim- Hide quoted text -

- Show quoted text -