Thanks a lot folks,
You are great!!
"Peo Sjoblom" wrote in message
...
Column with values starting in A2 going down
=OFFSET($A$2,COLUMN(A:A)-1,)
copy across and it will return A2, A3, A4 etc
Row with values starting in D2
=OFFSET($D$2,,ROW(1:1)-1,)
copy down and it will return D2, E2, F2 etc
--
Regards,
Peo Sjoblom
"markx" wrote in message
...
Thanks Julie,
In fact, I've tested this function just before, but as you pointed it
out,
it doesn't work by dragging it.
I remember that some time ago, I've found somewhere on the net two
functions
that work as I would like, but concern only transposing rows to columns.
One involves INDIRECT, ADDRESS and ROW functions, the other goes with
INDEX
and ROW function. Unfortunately I can't find them back right now to
quote
them directly.
While searching, I've just found something similar on the groups, I post
it
here for the illustration purposes, maybe this could help you imagine a
"general" formula covering my problem (unfortunately I'm unable to do it
by
myself:-(:
=INDEX(Sheet1!$1:$1,ROW()*2-1) = this one is supposed to skip every
second
value, still row to column
or
=INDIRECT("Summary!"&ADDRESS(38;ROW(1:1);4)) = still row to column, a
particular case
or
=INDIRECT("Summary!"&SUBSTITUTE(ADDRESS(1;ROW(1:1) ;4);"1";"")&"38") =
still
row to column, same post as before
Thanks once again for your help and FU on this!
Mark
---------------------
"JulieD" wrote in message
...
Hi
not sure if it fits the description of not too complex and doesn't
work
by
dragging, but there is a transpose function
say you have
........A..........B
1.....Cat........10
2.....Dog.......15
3....Rat..........20
and you want to transpose this table to the range A5:C6
select A5:C6
type
=TRANSPOSE(A1:B3)
and then press Control & Shift & Enter - not just Enter and the data
will
be transposed.
Cheers
JulieD
"markx" wrote in message
...
Hello everybody,
I'm looking for a formula (not VBA nor "Paste Special/Transpose")
that
would
transpose columns to rows (or vice versa) by simple dragging of the
cell.
Are you aware of any, hopefully not too complex?
Thanks a lot for your help on this,
Mark
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