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Posted to microsoft.public.excel.worksheet.functions
Farah Farah is offline
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Default Searching for a value in an Array

Thanks Bob, it is working great, but why do I need to press CTRL+SHIFT+ENTER
to evalluate this function

Regards,
Farah

"Bob Phillips" wrote:

This works fine for me

=INDEX(C1:C100,MATCH(1,(B1:B100="LEBANON")*(A1:A10 0="D51238K-QS USE XJ
Version 13458"),0))

although I do notice that all the machines are unique

--
HTH

Bob Phillips

(replace somewhere in email address with gmail if mailing direct)

"Farah" wrote in message
...
I attached below the data, I am sorry it is not tidy enough but the first
column is the machine model, then you can see the country and then the

price.

D28886-QS Dewalt Die Grinder. 710W variable speed 13456 IRAQ 137 USD
D28886-QS Dewalt Die Grinder. 710W variable speed 13457 JORDAN 137 USD
D28886-QS Dewalt Die Grinder. 710W variable speed 13458 LEBANON 137 USD
D28886-QS Dewalt Die Grinder. 710W variable speed 13459 SYRIA 137 USD
D28886-QS Dewalt Die Grinder. 710W variable speed 13460 EGYPT 137 USD
D28886-QS Dewalt Die Grinder. 710W variable speed 13461 LIBYA 126 USD
D28886-QS Dewalt Die Grinder. 710W variable speed 13462 MOROCCO 116 EUR
D28886-QS Dewalt Die Grinder. 710W variable speed 13463 TUNISIA 134 EUR
D28886-QS Dewalt Die Grinder. 710W variable speed 13464 ALGERIA 140.36 USD
D51238K-QS USE XJ Version 13457 JORDAN 122.9 USD
D51238K-QS USE XJ Version 13458 LEBANON 122.9 USD
D51238K-QS USE XJ Version 13459 SYRIA 117 USD
D51238K-QS USE XJ Version 13460 EGYPT 122.9 USD
D51238K-QS USE XJ Version 13461 LIBYA 125 USD
D51238K-QS USE XJ Version 13462 MOROCCO 110 EUR
D51238K-QS USE XJ Version 13463 TUNISIA 120 EUR
D51238K-XJ 18 GA 50mm BRAD NAILER KIT 13456 IRAQ 132.3 USD
D51238K-XJ 18 GA 50mm BRAD NAILER KIT 13457 JORDAN 129 USD
D51238K-XJ 18 GA 50mm BRAD NAILER KIT 13458 LEBANON 129 USD
D51238K-XJ 18 GA 50mm BRAD NAILER KIT 13459 SYRIA 129 USD
D51238K-XJ 18 GA 50mm BRAD NAILER KIT 13460 EGYPT 129 USD
D51238K-XJ 18 GA 50mm BRAD NAILER KIT 13461 LIBYA 131.3 USD
D51238K-XJ 18 GA 50mm BRAD NAILER KIT 13462 MOROCCO 115.5 EUR
D51238K-XJ 18 GA 50mm BRAD NAILER KIT 13464 ALGERIA 139.76 USD
D51256K-QS USE XJ VERSION 13456 IRAQ 183.8 USD

"Bob Phillips" wrote:

I completely understand how your data is laid out and the formula I gave

you
should do what you want.

Show me the exact formula that you used. an example of the data would

help
too.

--
HTH

Bob Phillips

(replace somewhere in email address with gmail if mailing direct)

"Farah" wrote in message
...
It gave me an error which is #NUM though I checked it many times. The
point
is that in the countries list, the country is repeated many times, and

in
the
machine model column, the machine is repeated many times, you need to
create
a lookup function which will search for the machine and then when it
founds
the machine search in another column for the country and then when

both
the
machine and the country matches your search criteria you need to get

the
price from another column, which means basically that you have a two
columns
lookup procedure.

Regards,

"Bob Phillips" wrote:

Which is exactly what we gave you. Did you try it? what happened

when
you
did?

--
HTH

Bob Phillips

(replace somewhere in email address with gmail if mailing direct)

"Farah" wrote in message
...
Guys,

It is not working, see I can pass you the files if possible just

tell
me
how
as I am new to this whole thing. The point is that I have many
machines
for
one country and I have many countries, to give you an idea, I have
seven
coutries and for each country and I have more than three hundred
machines
prices. The system given me a dupm showing in one column the

country
name
and
in another column the machine name and then the price. I need a
function
that
checks the country in one column and in the other columnn it

checks
the
machine, if both are OK then it should give me the price which is

in
another
column.

Regards,
Farah

"Aladin Akyurek" wrote:

Probably it's easier to understand a bit faster version...


=INDEX(C1:C100,MATCH(1,IF(A1:A100="country",IF(B1: B100="machine",1)),0))

which still needs to be confirmed with control+shift+enter.

Jim May wrote:
Bob,
I'm getting closer and closer to understanding this stuff, but

in
this
example there is one small piece I haven't got yet,

Your Match() has 3 elements:
1) the 1,
2) the combination of the ranges (Col A and ColB as one
parameter)
3) the 0, which is an exact match)

So 1 (in this case) is the lookup value, hummmm.. not sure

I'm
getting the
meaning here - I take 1 to be the value I'm looking for,
confused

Tks in Advance,
Jim


"Bob Phillips" wrote:


=INDEX(C1:C100,MATCH(1,(A1:A100="country")*(B1:B10 0="machine"),0))

which is an array formula, it should be committed with
Ctrl-Shift-Enter, not
just Enter.

--
HTH

Bob Phillips

(replace somewhere in email address with gmail if mailing dir

ect)

"Farah" wrote in message
...
I have a master price list were I have in column A the

country
name,
and
in
column B the machine model number and in column C the price.
Obviously you can find the same machine for many countries

with
different
prices, I need a formula were I can extract for a certain
country
the
price
of a certain machine.