Maybe...

Option Explicit
Sub testme()
Dim iRow As Long
with Activesheet
For iRow = 65 To 169 Step 52 'change 169 to 1261 when you're ready!
If .Cells(iRow, "F").Value < 0 Then
.Cells(Row, "A").Resize(52, 99).PrintOut preview:=True
End If
Next iRow
End With
End Sub

I assumed that the start of the page is column A of that same row as the one
being checked. And you want to print 99 columns. You'll have to change that or
at least share how to determine both those things.

And I did a print preview to save paper when you're testing. And I used row 169
as my last check--change that when you're ready to try it for real.


Gerard Sanchez wrote:

Can anybody help??

"KC" wrote in message
...
That is a pseudo code, not actual code.
The macro recorder can help you.


"Gerard Sanchez" wrote in message
...
Hi KC

Just tested the code as shown and I got a syntax error?

Sub PrintActivePages()

For i = 65 To 1261 Step 52
If Range("F" & i) < 0 Then
set print range to rows (i, i+51) <--------syntax error here
PrintOut
End If
Next i

End Sub



"KC" wrote in message
...
Maybe

for i=65 to 1261 step 52
if range("F" & i)<0 then
set print range to rows (i, i+51)
printout
end if
next i

"Gerard Sanchez" wrote in message
...
Hi,

Each worksheet has 25 pages in it.
Some have values some don't.

I was wondering if anybody cen help me with a Module Level Macro
that lets me print pages provided a cell on that page is not equal to
zero (0)

Here it is:

Print page two if F65 < 0
Print page three if F117 < 0
Print page four if F169 < 0
Print page five if F221 < 0

and on . . . until page 25 if cell F1261 < 0

(pattern is every 52 cells beginning with F65 and ending with F1261)

Anybody??










--

Dave Peterson