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StevenL
 
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Default index,match + 1 cell below?

if you are using the index/match combination function is it possible to index
the row below the result. In other words is it possible to take result of
index(a1:a5,match(c1,b1:b5),0)) and add one row.

Thanks most helpful ones
ST
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Bob Phillips
 
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Of course, add 1

=INDEX(A1:A5,MATCH(C1,B1:B5)+1,0)

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HTH

RP
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"StevenL" wrote in message
...
if you are using the index/match combination function is it possible to

index
the row below the result. In other words is it possible to take result

of
index(a1:a5,match(c1,b1:b5),0)) and add one row.

Thanks most helpful ones
ST



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Aladin Akyurek
 
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Since you appear to look up with match-type (range_lookup in MS
parlance) set to 1/TRUE, I'll gamble that you probably want:

=INDEX($B$1:$B$5,MATCH(C1,$A$1:$A$5)+(LOOKUP(C1,$A $1:$A$5)<C1))

Otherwise, see Bob Phillips's reply.

StevenL wrote:
if you are using the index/match combination function is it possible to index
the row below the result. In other words is it possible to take result of
index(a1:a5,match(c1,b1:b5),0)) and add one row.

Thanks most helpful ones
ST

  #4   Report Post  
SteveT
 
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"StevenL" wrote:

if you are using the index/match combination function is it possible to index
the row below the result. In other words is it possible to take result of
index(a1:a5,match(c1,b1:b5),0)) and add one row.

Thanks most helpful ones
ST

  #5   Report Post  
SteveT
 
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BOB / ALADIN, both of replies provided solution.

Thank you both greatly!

"StevenL" wrote:

if you are using the index/match combination function is it possible to index
the row below the result. In other words is it possible to take result of
index(a1:a5,match(c1,b1:b5),0)) and add one row.

Thanks most helpful ones
ST

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