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index,match + 1 cell below?
if you are using the index/match combination function is it possible to index
the row below the result. In other words is it possible to take result of index(a1:a5,match(c1,b1:b5),0)) and add one row. Thanks most helpful ones ST |
Of course, add 1
=INDEX(A1:A5,MATCH(C1,B1:B5)+1,0) -- HTH RP (remove nothere from the email address if mailing direct) "StevenL" wrote in message ... if you are using the index/match combination function is it possible to index the row below the result. In other words is it possible to take result of index(a1:a5,match(c1,b1:b5),0)) and add one row. Thanks most helpful ones ST |
Since you appear to look up with match-type (range_lookup in MS
parlance) set to 1/TRUE, I'll gamble that you probably want: =INDEX($B$1:$B$5,MATCH(C1,$A$1:$A$5)+(LOOKUP(C1,$A $1:$A$5)<C1)) Otherwise, see Bob Phillips's reply. StevenL wrote: if you are using the index/match combination function is it possible to index the row below the result. In other words is it possible to take result of index(a1:a5,match(c1,b1:b5),0)) and add one row. Thanks most helpful ones ST |
"StevenL" wrote: if you are using the index/match combination function is it possible to index the row below the result. In other words is it possible to take result of index(a1:a5,match(c1,b1:b5),0)) and add one row. Thanks most helpful ones ST |
BOB / ALADIN, both of replies provided solution.
Thank you both greatly! "StevenL" wrote: if you are using the index/match combination function is it possible to index the row below the result. In other words is it possible to take result of index(a1:a5,match(c1,b1:b5),0)) and add one row. Thanks most helpful ones ST |
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