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Thank you. It's quite clever.
tj "Rob van Gelder" wrote: MID(A1, ROW(INDIRECT("1:" & LEN(A1))), 1) allows the string to be split into individual entries CODE(..) returns the ascii code for each character - I'm looking for numbers which are in the range 48 to 57 for "0" to "9" Then subtract 52.5, which is midway between 48 and 57 48+(57-48)/2 where (57-48)/2 = 4.5 ABS turns negative numbers to positive. So this means ascii codes for numbers are from 0 to 4.5 Check to see whether any of the numbers are less than or equal to 4.5 which returns a series of TRUE/FALSE -- turns TRUE, FALSE to 1, 0 SUMPRODUCT adds the entries of an array. 0 means the count of characters which were identified as numbers -- Rob van Gelder - http://www.vangelder.co.nz/excel "tjtjjtjt" wrote in message ... Would you mind explaining why this formula works? Thanks, tj "Rob van Gelder" wrote: =SUMPRODUCT(--(ABS(CODE(MID(A1, ROW(INDIRECT("1:" & LEN(A1))), 1)) - 52.5)<=4.5))0 -- Rob van Gelder - http://www.vangelder.co.nz/excel "Fletcher" wrote in message ... I tried that, but if the cell has numbers and text, it replies back with FALSE. I would like to be able to determine if any part of the cell contents is a number, even if the string starts with, or contains letters. Thanks! "LanceB" wrote in message ... =ISNUMBER(a1) "Fletcher" wrote: I want a formula that will tell me if a given cell has a number in it, so it evaluates the type of data. I looked in the help files and couldn't figure this out. Thanks, Craig |
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