Hi All,

Using a Dynamic Named Range "Data", I would like a Formula to return the Row
Number of the "LAST" instance of a duplicate numeric value - repeating twice
consecutively in the same column.

Thanks
Sam

--
Message posted via OfficeKB.com
http://www.officekb.com/Uwe/Forums.a...tions/200607/1

Just to be clear, if A2:A10 contains the following data...

6
6
9
3
5
7
7
7
4

....what would be your expected result?

In article <62cefd3c3cc94@uwe, "Sam via OfficeKB.com" <u4102@uwe
wrote:

Hi All,

Using a Dynamic Named Range "Data", I would like a Formula to return the Row
Number of the "LAST" instance of a duplicate numeric value - repeating twice
consecutively in the same column.

Thanks
Sam

Hi Domenic,

A column will contain multiple instances of the same numerical value, so A2:
A10 will contain only numeric value 30. This numeric value will at times have
consecutive duplicates (x2).

Cheers,
Sam

Domenic wrote:
Just to be clear, if A2:A10 contains the following data...
6
6
9
3
5
7
7
7
4
...what would be your expected result?

--
Message posted via http://www.officekb.com

Are you saying that A2:A10 might look something like this... ?

30


30
30


30
30

If so, what result would you expect? And to be clear, will there ever
be an instance where there's three or more consecutive values?

In article <62d036ea3708e@uwe, "Sam via OfficeKB.com" <u4102@uwe
wrote:

Hi Domenic,

A column will contain multiple instances of the same numerical value, so A2:
A10 will contain only numeric value 30. This numeric value will at times have
consecutive duplicates (x2).

Cheers,
Sam

Hi Domenic,

Domenic wrote:
Are you saying that A2:A10 might look something like this... ?

Yes

30

30
30

30
30 Row Number of LAST 30 with two consecutive instances

If so, what result would you expect? And to be clear, will there ever
be an instance where there's three or more consecutive values?

I would expect the Row Number of the LAST 30 with two consecutive instances.
There may be instances with three or more consecutive values BUT I only
require the LAST Row Number of those with two consecutive instances.

Cheers,
Sam

--
Message posted via http://www.officekb.com

First, assuming that Sheet1, Column A, starting at A2, contains the
data, change the reference for the defined named 'Data' to...

=Sheet1!$A$2:INDEX(Sheet1!$A$2:$A$65536,MATCH(9.99 999999999999E+307,Sheet
1!$A$2:$A$65536)+1)

Then, let B2 contain the number of interest, such as 30, and try the
following formula which needs to be confirmed with CONTROL+SHIFT+ENTER,
not just ENTER...

=LOOKUP(2,1/(FREQUENCY(IF(Data=B2,ROW(Data)-MIN(ROW(Data))+1),IF(Data<B2
,MATCH(ROW(Data),ROW(Data),0),B2+1))=2),ROW(Data))-1

Note that if you'd like to check for the last instance of 3 consecutive
values, change =2 to =3, and so on.

Hope this helps!

In article <62d0c6b91c44f@uwe, "Sam via OfficeKB.com" <u4102@uwe
wrote:

Hi Domenic,

Domenic wrote:
Are you saying that A2:A10 might look something like this... ?

Yes

30

30
30

30
30 Row Number of LAST 30 with two consecutive instances

If so, what result would you expect? And to be clear, will there ever
be an instance where there's three or more consecutive values?

I would expect the Row Number of the LAST 30 with two consecutive instances.
There may be instances with three or more consecutive values BUT I only
require the LAST Row Number of those with two consecutive instances.

Cheers,
Sam