Home |
Search |
Today's Posts |
#3
![]()
Posted to microsoft.public.excel.worksheet.functions
|
|||
|
|||
![]()
Thank you. I just had the OR in the wrong place.
"bpeltzer" wrote: I'd just apply the OR to multiple ISNUMBER(MATCH()) constructs: =if(or(isnumber(match($I3,'MSP Listing'!$A$6:$A$2260,0)),isnumber(match($I3,'MSP Listing'!$B$6:$B$2260,0))),"Yes","No") "Joe Gieder" wrote: First, thank you for looking at this and your help. I'm trying to use the formula below to tell me if a cell value in I3 is listed in either A6:A2260 OR B6:B2260 =IF(ISNUMBER(MATCH($I3,OR(('MSP Listing'!$A$6:$A$2260),('MSP Listing'!$B$6:$B$2260)),0)),"Yes","No") Can this be accomplished in this condensed formula or do I need to write a multiple IF formula? The way it's written above I receive No but the part does exist in A, it should say Yes. Again, thank you for all your help Joe |
Thread Tools | Search this Thread |
Display Modes | |
|
|
![]() |
||||
Thread | Forum | |||
Match Index | Excel Worksheet Functions | |||
Look up data in colum a and find match in colum b | Excel Discussion (Misc queries) | |||
Look up data in colum a and find match in colum b | Excel Discussion (Misc queries) | |||
Find a match that;s not exact | Excel Worksheet Functions | |||
Vlookup, Index & Match | Excel Worksheet Functions |