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#2
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One way:
A1: <start date A2: <end date A3: =DATEDIF(A1,A2,"y") & " years, " & DATEDIF(A1,A2,"ym") & " months" See http://cpearson.com/excel/datedif.htm for more documentation on DATEDIF(). In article , David Picken <David wrote: |
#3
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=DATEDIF(date1, date2,"y") for years
=DATEDIF(date1, date2, "ym") for extra months HTH -- AP "David Picken" <David a écrit dans le message de ... |
#4
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I have a spreadsheet with a date inducted and a date it needs to be replaced.
How do I get a cell with the remaining days between the dates and it update daily? "Ardus Petus" wrote: =DATEDIF(date1, date2,"y") for years =DATEDIF(date1, date2, "ym") for extra months HTH -- AP "David Picken" <David a écrit dans le message de ... |
#5
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=DATEDIF(date1, date2,"d") for days between date1 & date2
HTH -- AP "Brandon" a écrit dans le message de ... I have a spreadsheet with a date inducted and a date it needs to be replaced. How do I get a cell with the remaining days between the dates and it update daily? "Ardus Petus" wrote: =DATEDIF(date1, date2,"y") for years =DATEDIF(date1, date2, "ym") for extra months HTH -- AP "David Picken" <David a écrit dans le message de ... |
#6
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One way:
A1: <date inducted A2: <date to be replaced A3: =A2-A1 format A3 as General or Number. No idea how to update it daily unless you specify how either of the dates change. In article , Brandon wrote: I have a spreadsheet with a date inducted and a date it needs to be replaced. How do I get a cell with the remaining days between the dates and it update daily? |
#7
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![]() Brandon Wrote: I have a spreadsheet with a date inducted and a date it needs to be replaced. How do I get a cell with the remaining days between the dates and it update daily? "Ardus Petus" wrote: =DATEDIF(date1, date2,"y") for years =DATEDIF(date1, date2, "ym") for extra months HTH -- AP "David Picken" <David a écrit dans le message de ... In general to get the difference in days between two dates you only need =B1-A1 where B1 is the later date format as general In your case it looks like you need the difference in days between today and your replacement date - if replacement date in in C1 =C1-today() format as general -- daddylonglegs ------------------------------------------------------------------------ daddylonglegs's Profile: http://www.excelforum.com/member.php...o&userid=30486 View this thread: http://www.excelforum.com/showthread...hreadid=524789 |
#8
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#9
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That worked but I worded the problem wrong.
I have a part inducted on 1-1-06 that has a life span of 1825 days. How can I create a formula that will give me the days remaining in a column and have that number updated daily? I'm using Excel 2003. "Ardus Petus" wrote: =DATEDIF(date1, date2,"d") for days between date1 & date2 HTH -- AP "Brandon" a écrit dans le message de ... I have a spreadsheet with a date inducted and a date it needs to be replaced. How do I get a cell with the remaining days between the dates and it update daily? "Ardus Petus" wrote: =DATEDIF(date1, date2,"y") for years =DATEDIF(date1, date2, "ym") for extra months HTH -- AP "David Picken" <David a écrit dans le message de ... |
#10
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![]() =1825+DATE(2006,1,1)-TODAY() format as general -- daddylonglegs ------------------------------------------------------------------------ daddylonglegs's Profile: http://www.excelforum.com/member.php...o&userid=30486 View this thread: http://www.excelforum.com/showthread...hreadid=524789 |
#11
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1745
"daddylonglegs" wrote: =1825+DATE(2006,1,1)-TODAY() format as general -- daddylonglegs ------------------------------------------------------------------------ daddylonglegs's Profile: http://www.excelforum.com/member.php...o&userid=30486 View this thread: http://www.excelforum.com/showthread...hreadid=524789 |
#12
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It returned 1745
"Brandon" wrote: 1745 "daddylonglegs" wrote: =1825+DATE(2006,1,1)-TODAY() format as general -- daddylonglegs ------------------------------------------------------------------------ daddylonglegs's Profile: http://www.excelforum.com/member.php...o&userid=30486 View this thread: http://www.excelforum.com/showthread...hreadid=524789 |
#13
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![]() Is that not correct? You wanted the days remaining. If it shows 1745 today it will show 1744 tomorrow and so on until it reaches zero on 31st December 2010. -- daddylonglegs ------------------------------------------------------------------------ daddylonglegs's Profile: http://www.excelforum.com/member.php...o&userid=30486 View this thread: http://www.excelforum.com/showthread...hreadid=524789 |
#14
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Well of course had I closed the application and reopened it and used my
brain. Thank you so much for all the help. It seems to work like a charm. I will try it on the main sheet and see what happens. This has been very helpful. "daddylonglegs" wrote: Is that not correct? You wanted the days remaining. If it shows 1745 today it will show 1744 tomorrow and so on until it reaches zero on 31st December 2010. -- daddylonglegs ------------------------------------------------------------------------ daddylonglegs's Profile: http://www.excelforum.com/member.php...o&userid=30486 View this thread: http://www.excelforum.com/showthread...hreadid=524789 |
#15
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Does the 360 days a year affect the calculations? I saw where Excel uses 360
days in the year instead of 365. "daddylonglegs" wrote: Is that not correct? You wanted the days remaining. If it shows 1745 today it will show 1744 tomorrow and so on until it reaches zero on 31st December 2010. -- daddylonglegs ------------------------------------------------------------------------ daddylonglegs's Profile: http://www.excelforum.com/member.php...o&userid=30486 View this thread: http://www.excelforum.com/showthread...hreadid=524789 |
#16
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![]() Using the formula I posted the calculation will be correct. There is a DAYS360 function in Excel which uses a 360 day year for accounting purposes but, other than that Excel will calculate using 365 day or 366 day years as appropriate -- daddylonglegs ------------------------------------------------------------------------ daddylonglegs's Profile: http://www.excelforum.com/member.php...o&userid=30486 View this thread: http://www.excelforum.com/showthread...hreadid=524789 |
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