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![]() I have 12 columns of data, looking like this: (At Least) (But Less than) 0 1 2 3 4 5 6 7 8 9 10 0 105 0 0 0 0 0 0 0 0 0 0 105 110 1 2 0 0 0 0 0 0 0 110 115 2 3 4 0 0 0 0 0 0 etc. I have two things to pinpoint exactly which number I want on the left, the first is the number that falls in between the atleast and less than, and a number between 0-10 that chooses which column to select. eg. The first number they give is 108 and the second number they give is 1, so it should fall under the third row (because 108 is between 105 and 110) and the number it should return is 2 because that is under the #1 column. Sounds pretty complex to me, hope someone can make sense out of it and help me out, thanks :). -- Jedispiff ------------------------------------------------------------------------ Jedispiff's Profile: http://www.excelforum.com/member.php...o&userid=32099 View this thread: http://www.excelforum.com/showthread...hreadid=518567 |
#2
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It's not that complex but your posted table looks a bit strange, I doubt it
really looks like that? -- Regards, Peo Sjoblom Northwest Excel Solutions www.nwexcelsolutions.com (remove ^^ from email address) Portland, Oregon "Jedispiff" wrote in message ... I have 12 columns of data, looking like this: (At Least) (But Less than) 0 1 2 3 4 5 6 7 8 9 10 0 105 0 0 0 0 0 0 0 0 0 0 105 110 1 2 0 0 0 0 0 0 0 110 115 2 3 4 0 0 0 0 0 0 etc. I have two things to pinpoint exactly which number I want on the left, the first is the number that falls in between the atleast and less than, and a number between 0-10 that chooses which column to select. eg. The first number they give is 108 and the second number they give is 1, so it should fall under the third row (because 108 is between 105 and 110) and the number it should return is 2 because that is under the #1 column. Sounds pretty complex to me, hope someone can make sense out of it and help me out, thanks :). -- Jedispiff ------------------------------------------------------------------------ Jedispiff's Profile: http://www.excelforum.com/member.php...o&userid=32099 View this thread: http://www.excelforum.com/showthread...hreadid=518567 |
#3
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![]() Well, there are 132 more lines to it, and that's not exactly what it looks like, but it's a good approximation -- Jedispiff ------------------------------------------------------------------------ Jedispiff's Profile: http://www.excelforum.com/member.php...o&userid=32099 View this thread: http://www.excelforum.com/showthread...hreadid=518567 |
#4
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Hi
At start, dismiss LessThan column at all, and start, so your table will look like this AtL 1 2 3 4 5 6 7 8 9 10 0 0 0 0 0 0 0 0 0 0 0 105 1 2 0 0 0 0 0 0 0 0 110 2 3 4 0 0 0 0 0 0 0 115 The formula for conditions 108 and 1 =OFFSET(A1,MATCH(108,A2:A5,1),1) ,for 33 and 8 =OFFSET(A1,MATCH(33,A2:A5,1),8) , etc. -- Arvi Laanemets ( My real mail address: arvi.laanemets<attarkon.ee ) "Jedispiff" wrote in message ... I have 12 columns of data, looking like this: (At Least) (But Less than) 0 1 2 3 4 5 6 7 8 9 10 0 105 0 0 0 0 0 0 0 0 0 0 105 110 1 2 0 0 0 0 0 0 0 110 115 2 3 4 0 0 0 0 0 0 etc. I have two things to pinpoint exactly which number I want on the left, the first is the number that falls in between the atleast and less than, and a number between 0-10 that chooses which column to select. eg. The first number they give is 108 and the second number they give is 1, so it should fall under the third row (because 108 is between 105 and 110) and the number it should return is 2 because that is under the #1 column. Sounds pretty complex to me, hope someone can make sense out of it and help me out, thanks :). -- Jedispiff ------------------------------------------------------------------------ Jedispiff's Profile: http://www.excelforum.com/member.php...o&userid=32099 View this thread: http://www.excelforum.com/showthread...hreadid=518567 |
#5
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![]() Thanks for the help, made it work :) -- Jedispiff ------------------------------------------------------------------------ Jedispiff's Profile: http://www.excelforum.com/member.php...o&userid=32099 View this thread: http://www.excelforum.com/showthread...hreadid=518567 |
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