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is there any way to have excel return the next largest value that is MORE
than the 'lookup_value' when 'range_lookup' = 'true'? (it normally defaults to the next largest value that is LESS) or is there another way around this problem? eg - my lookup_value is 105; my table array may or may noy have 105, but always has numbers higher than 105 - the desired value to return is for the next number availble after 105. regards. |
#2
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You can sort your list in descending order and use the MATCH() function with
the third argument of -1. You'll probably have to use the MATCH() within an INDEX() function "mkbatch" wrote: is there any way to have excel return the next largest value that is MORE than the 'lookup_value' when 'range_lookup' = 'true'? (it normally defaults to the next largest value that is LESS) or is there another way around this problem? eg - my lookup_value is 105; my table array may or may noy have 105, but always has numbers higher than 105 - the desired value to return is for the next number availble after 105. regards. |
#3
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If your table is already sorted ascending and you can't or don't want to
sort your table descending: Array entered using the key combo of CTRL,SHIFT,ENTER: A1 = lookup value =INDEX(C1:C10,MATCH(TRUE,B1:B10=A1,0)) Biff "mkbatch" wrote in message ... is there any way to have excel return the next largest value that is MORE than the 'lookup_value' when 'range_lookup' = 'true'? (it normally defaults to the next largest value that is LESS) or is there another way around this problem? eg - my lookup_value is 105; my table array may or may noy have 105, but always has numbers higher than 105 - the desired value to return is for the next number availble after 105. regards. |
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