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RJL0323
 
Posts: n/a
Default Counting Unique Values


Hello All,
I have a question related to counting unique values in a column of
data. I will try to illustrate my question. I have a column of data
with 1000 rows. In this column there are duplicated values. I would
like to be able to use a function count how many unique values are in
the column. Let's say there were 4 duplicates of 250 values in the
column. I would like to be able to write a function to calculate the
250. I am very familiar with Excel and am able to acheive the number
through subtotals and/or pivot tables. I know I can find how many
instances one specific value appears in the column through sumproduct
and/or countif statements, but the function to calculate the number of
unique values has really got me stumped.

Does anyone have any ideas?

Thanks in advance!!
RJ


--
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Bob Phillips
 
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Default Counting Unique Values

=SUMPRODUCT(1/COUNTIF(A1:A1000,A1:A1000))

--

HTH

Bob Phillips

(remove nothere from the email address if mailing direct)

"RJL0323" wrote in
message ...

Hello All,
I have a question related to counting unique values in a column of
data. I will try to illustrate my question. I have a column of data
with 1000 rows. In this column there are duplicated values. I would
like to be able to use a function count how many unique values are in
the column. Let's say there were 4 duplicates of 250 values in the
column. I would like to be able to write a function to calculate the
250. I am very familiar with Excel and am able to acheive the number
through subtotals and/or pivot tables. I know I can find how many
instances one specific value appears in the column through sumproduct
and/or countif statements, but the function to calculate the number of
unique values has really got me stumped.

Does anyone have any ideas?

Thanks in advance!!
RJ


--
RJL0323
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  #3   Report Post  
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Bill Kuunders
 
Posts: n/a
Default Counting Unique Values

Bob, I check this news group frequently as a means to learn stuff.

Could you please explain why and how your formula works?

Thank You
--
Greetings from New Zealand
Bill K



"Bob Phillips" wrote in message
...
=SUMPRODUCT(1/COUNTIF(A1:A1000,A1:A1000))

--

HTH

Bob Phillips

(remove nothere from the email address if mailing direct)

"RJL0323" wrote in
message ...

Hello All,
I have a question related to counting unique values in a column of
data. I will try to illustrate my question. I have a column of data
with 1000 rows. In this column there are duplicated values. I would
like to be able to use a function count how many unique values are in
the column. Let's say there were 4 duplicates of 250 values in the
column. I would like to be able to write a function to calculate the
250. I am very familiar with Excel and am able to acheive the number
through subtotals and/or pivot tables. I know I can find how many
instances one specific value appears in the column through sumproduct
and/or countif statements, but the function to calculate the number of
unique values has really got me stumped.

Does anyone have any ideas?

Thanks in advance!!
RJ


--
RJL0323
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Peo Sjoblom
 
Posts: n/a
Default Counting Unique Values

I would personally use the variant

=SUMPRODUCT(--(A1:A1000<""),1/COUNTIF(A1:A1000,A1:A1000&""))

otherwise you'll get DIV/0 errors if there are blank cells, it works as
follows

the 1/countif part returns an array of numbers, if there is one value unique
it will return 1,
if there are 2 values that are the same it will return 2 times 0.5 (1/2 =
0.5), if 3 it will return 0.333333, 4 0.25 and so on

assume we have this in A1:A10

1
2
3
4
65
6
1
2
3
4


it would be 6 unique values, the 1/countif returns

{0.5;0.5;0.5;0.5;1;1;0.5;0.5;0.5;0.5}

sumproduct will sum them to return 6, if we change the last number 4 to 1 so
there would be 3 1

{0.333333333333333;0.5;0.5;1;1;1;0.333333333333333 ;0.5;0.5;0.333333333333333}

still returns the total of 6

I believe former MVP Dave Hager was the originator of it although it has
been converted from

=SUM(1/COUNTIF))

to sumproduct thus it can be entered normally

--

Regards,

Peo Sjoblom

Northwest Excel Solutions

Portland, Oregon




"Bill Kuunders" wrote in message
...
Bob, I check this news group frequently as a means to learn stuff.

Could you please explain why and how your formula works?

Thank You
--
Greetings from New Zealand
Bill K



"Bob Phillips" wrote in message
...
=SUMPRODUCT(1/COUNTIF(A1:A1000,A1:A1000))

--

HTH

Bob Phillips

(remove nothere from the email address if mailing direct)

"RJL0323" wrote in
message ...

Hello All,
I have a question related to counting unique values in a column of
data. I will try to illustrate my question. I have a column of data
with 1000 rows. In this column there are duplicated values. I would
like to be able to use a function count how many unique values are in
the column. Let's say there were 4 duplicates of 250 values in the
column. I would like to be able to write a function to calculate the
250. I am very familiar with Excel and am able to acheive the number
through subtotals and/or pivot tables. I know I can find how many
instances one specific value appears in the column through sumproduct
and/or countif statements, but the function to calculate the number of
unique values has really got me stumped.

Does anyone have any ideas?

Thanks in advance!!
RJ


--
RJL0323
------------------------------------------------------------------------
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Bill Kuunders
 
Posts: n/a
Default Counting Unique Values

Thanks Peo,

When I only enter = 1/COUNTIF(A1:A1000,A1:A1000&"") the answer is 0.5
I suppose it is showing me the most frequent occuring in the array??

Thanks again, excellent formula
Bill Kuunders

"Peo Sjoblom" wrote in message
...
I would personally use the variant

=SUMPRODUCT(--(A1:A1000<""),1/COUNTIF(A1:A1000,A1:A1000&""))

otherwise you'll get DIV/0 errors if there are blank cells, it works as
follows

the 1/countif part returns an array of numbers, if there is one value
unique it will return 1,
if there are 2 values that are the same it will return 2 times 0.5 (1/2 =
0.5), if 3 it will return 0.333333, 4 0.25 and so on

assume we have this in A1:A10

1
2
3
4
65
6
1
2
3
4


it would be 6 unique values, the 1/countif returns

{0.5;0.5;0.5;0.5;1;1;0.5;0.5;0.5;0.5}

sumproduct will sum them to return 6, if we change the last number 4 to 1
so there would be 3 1

{0.333333333333333;0.5;0.5;1;1;1;0.333333333333333 ;0.5;0.5;0.333333333333333}

still returns the total of 6

I believe former MVP Dave Hager was the originator of it although it has
been converted from

=SUM(1/COUNTIF))

to sumproduct thus it can be entered normally

--

Regards,

Peo Sjoblom

Northwest Excel Solutions

Portland, Oregon




"Bill Kuunders" wrote in message
...
Bob, I check this news group frequently as a means to learn stuff.

Could you please explain why and how your formula works?

Thank You
--
Greetings from New Zealand
Bill K



"Bob Phillips" wrote in message
...
=SUMPRODUCT(1/COUNTIF(A1:A1000,A1:A1000))

--

HTH

Bob Phillips

(remove nothere from the email address if mailing direct)

"RJL0323" wrote
in
message ...

Hello All,
I have a question related to counting unique values in a column of
data. I will try to illustrate my question. I have a column of data
with 1000 rows. In this column there are duplicated values. I would
like to be able to use a function count how many unique values are in
the column. Let's say there were 4 duplicates of 250 values in the
column. I would like to be able to write a function to calculate the
250. I am very familiar with Excel and am able to acheive the number
through subtotals and/or pivot tables. I know I can find how many
instances one specific value appears in the column through sumproduct
and/or countif statements, but the function to calculate the number of
unique values has really got me stumped.

Does anyone have any ideas?

Thanks in advance!!
RJ


--
RJL0323
------------------------------------------------------------------------
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http://www.excelforum.com/member.php...o&userid=19456
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Peo Sjoblom
 
Posts: n/a
Default Counting Unique Values

Actually, the 0.5 is the first value in the array, meaning that whatever is
in A1 occurs twice in the range

select B1:B10, with B1 as the active cell click in the formula bar and put
that formula, now enter it with ctrl + shift & enter, now if you sum B1:B10
you'll get the total of uniques, that is how array formulas can work

--

Regards,

Peo Sjoblom

Northwest Excel Solutions

Portland, Oregon




"Bill Kuunders" wrote in message
...
Thanks Peo,

When I only enter = 1/COUNTIF(A1:A1000,A1:A1000&"") the answer is 0.5
I suppose it is showing me the most frequent occuring in the array??

Thanks again, excellent formula
Bill Kuunders

"Peo Sjoblom" wrote in message
...
I would personally use the variant

=SUMPRODUCT(--(A1:A1000<""),1/COUNTIF(A1:A1000,A1:A1000&""))

otherwise you'll get DIV/0 errors if there are blank cells, it works as
follows

the 1/countif part returns an array of numbers, if there is one value
unique it will return 1,
if there are 2 values that are the same it will return 2 times 0.5 (1/2 =
0.5), if 3 it will return 0.333333, 4 0.25 and so on

assume we have this in A1:A10

1
2
3
4
65
6
1
2
3
4


it would be 6 unique values, the 1/countif returns

{0.5;0.5;0.5;0.5;1;1;0.5;0.5;0.5;0.5}

sumproduct will sum them to return 6, if we change the last number 4 to 1
so there would be 3 1

{0.333333333333333;0.5;0.5;1;1;1;0.333333333333333 ;0.5;0.5;0.333333333333333}

still returns the total of 6

I believe former MVP Dave Hager was the originator of it although it has
been converted from

=SUM(1/COUNTIF))

to sumproduct thus it can be entered normally

--

Regards,

Peo Sjoblom

Northwest Excel Solutions

Portland, Oregon




"Bill Kuunders" wrote in message
...
Bob, I check this news group frequently as a means to learn stuff.

Could you please explain why and how your formula works?

Thank You
--
Greetings from New Zealand
Bill K



"Bob Phillips" wrote in message
...
=SUMPRODUCT(1/COUNTIF(A1:A1000,A1:A1000))

--

HTH

Bob Phillips

(remove nothere from the email address if mailing direct)

"RJL0323" wrote
in
message ...

Hello All,
I have a question related to counting unique values in a column of
data. I will try to illustrate my question. I have a column of data
with 1000 rows. In this column there are duplicated values. I would
like to be able to use a function count how many unique values are in
the column. Let's say there were 4 duplicates of 250 values in the
column. I would like to be able to write a function to calculate the
250. I am very familiar with Excel and am able to acheive the number
through subtotals and/or pivot tables. I know I can find how many
instances one specific value appears in the column through sumproduct
and/or countif statements, but the function to calculate the number of
unique values has really got me stumped.

Does anyone have any ideas?

Thanks in advance!!
RJ


--
RJL0323
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http://www.excelforum.com/member.php...o&userid=19456
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Posted to microsoft.public.excel.worksheet.functions
Bob Phillips
 
Posts: n/a
Default Counting Unique Values

From the OPs post there was a full set of data, so in his case there was no
need to handle blanks.

--

HTH

Bob Phillips

(remove nothere from the email address if mailing direct)

"Peo Sjoblom" wrote in message
...
I would personally use the variant

=SUMPRODUCT(--(A1:A1000<""),1/COUNTIF(A1:A1000,A1:A1000&""))

otherwise you'll get DIV/0 errors if there are blank cells, it works as
follows

the 1/countif part returns an array of numbers, if there is one value

unique
it will return 1,
if there are 2 values that are the same it will return 2 times 0.5 (1/2 =
0.5), if 3 it will return 0.333333, 4 0.25 and so on

assume we have this in A1:A10

1
2
3
4
65
6
1
2
3
4


it would be 6 unique values, the 1/countif returns

{0.5;0.5;0.5;0.5;1;1;0.5;0.5;0.5;0.5}

sumproduct will sum them to return 6, if we change the last number 4 to 1

so
there would be 3 1


{0.333333333333333;0.5;0.5;1;1;1;0.333333333333333 ;0.5;0.5;0.333333333333333
}

still returns the total of 6

I believe former MVP Dave Hager was the originator of it although it has
been converted from

=SUM(1/COUNTIF))

to sumproduct thus it can be entered normally

--

Regards,

Peo Sjoblom

Northwest Excel Solutions

Portland, Oregon




"Bill Kuunders" wrote in message
...
Bob, I check this news group frequently as a means to learn stuff.

Could you please explain why and how your formula works?

Thank You
--
Greetings from New Zealand
Bill K



"Bob Phillips" wrote in message
...
=SUMPRODUCT(1/COUNTIF(A1:A1000,A1:A1000))

--

HTH

Bob Phillips

(remove nothere from the email address if mailing direct)

"RJL0323" wrote

in
message ...

Hello All,
I have a question related to counting unique values in a column of
data. I will try to illustrate my question. I have a column of data
with 1000 rows. In this column there are duplicated values. I would
like to be able to use a function count how many unique values are in
the column. Let's say there were 4 duplicates of 250 values in the
column. I would like to be able to write a function to calculate the
250. I am very familiar with Excel and am able to acheive the number
through subtotals and/or pivot tables. I know I can find how many
instances one specific value appears in the column through sumproduct
and/or countif statements, but the function to calculate the number of
unique values has really got me stumped.

Does anyone have any ideas?

Thanks in advance!!
RJ


--
RJL0323


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via135
 
Posts: n/a
Default Counting Unique Values


hi Peo!

for a single column of data the formula is ok!

can i use the same formula for data with more than one column with
duplicates?
for example

col"a" col"b" col"c" col"d"

xxx yyy 10 zzz
xyz abc 20 rst
yzx cab 10 mno
bac def 30 xyz
xyz abc 20 rst
xyz abc 10 rst
yzx cab 10 mno

-now i want to count the number of records excluding the duplicates!
in the above example 2nd & 5th, 3rd & 6th are duplicates.

if i make a count of total records without repetition, i must a get an
answer of 5 ie.(7-2)






Peo Sjoblom Wrote:
I would personally use the variant

=SUMPRODUCT(--(A1:A1000<""),1/COUNTIF(A1:A1000,A1:A1000&""))

otherwise you'll get DIV/0 errors if there are blank cells, it works
as
follows

the 1/countif part returns an array of numbers, if there is one value
unique
it will return 1,
if there are 2 values that are the same it will return 2 times 0.5 (1/2
=
0.5), if 3 it will return 0.333333, 4 0.25 and so on

assume we have this in A1:A10

1
2
3
4
65
6
1
2
3
4


it would be 6 unique values, the 1/countif returns

{0.5;0.5;0.5;0.5;1;1;0.5;0.5;0.5;0.5}

sumproduct will sum them to return 6, if we change the last number 4 to
1 so
there would be 3 1

{0.333333333333333;0.5;0.5;1;1;1;0.333333333333333 ;0.5;0.5;0.333333333333333}

still returns the total of 6

I believe former MVP Dave Hager was the originator of it although it
has
been converted from

=SUM(1/COUNTIF))

to sumproduct thus it can be entered normally

--

Regards,

Peo Sjoblom

Northwest Excel Solutions

Portland, Oregon




"Bill Kuunders" wrote in message
...
Bob, I check this news group frequently as a means to learn stuff.

Could you please explain why and how your formula works?

Thank You
--
Greetings from New Zealand
Bill K



"Bob Phillips" wrote in message
...
=SUMPRODUCT(1/COUNTIF(A1:A1000,A1:A1000))

--

HTH

Bob Phillips

(remove nothere from the email address if mailing direct)

"RJL0323"

wrote in
message

...

Hello All,
I have a question related to counting unique values in a column of
data. I will try to illustrate my question. I have a column of

data
with 1000 rows. In this column there are duplicated values. I

would
like to be able to use a function count how many unique values are

in
the column. Let's say there were 4 duplicates of 250 values in the
column. I would like to be able to write a function to calculate

the
250. I am very familiar with Excel and am able to acheive the

number
through subtotals and/or pivot tables. I know I can find how many
instances one specific value appears in the column through

sumproduct
and/or countif statements, but the function to calculate the number

of
unique values has really got me stumped.

Does anyone have any ideas?

Thanks in advance!!
RJ


--
RJL0323

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via135
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Aladin Akyurek
 
Posts: n/a
Default Counting Unique Values

1] If you download & install the morefunc.xll add-in:

=COUNTDIFF(A1:A7&"#"&B1:B7&"#"&C1:C7&"#"&D1:D7,,"" )

which needs to be confirmed with control+shift+enter, not just with enter.

2] With built-in functions:

=SUMPRODUCT(--((MATCH(A1:A7&"#"&B1:B7&"#"&C1:C7&"#"&D1:D7,A1:A7& "#"&B1:B7&"#"&C1:C7&"#"&D1:D7,0)=ROW(INDEX(A1:A7,0 ,0))-ROW(A1)+1)))


via135 wrote:
hi Peo!

for a single column of data the formula is ok!

can i use the same formula for data with more than one column with
duplicates?
for example

col"a" col"b" col"c" col"d"

xxx yyy 10 zzz
xyz abc 20 rst
yzx cab 10 mno
bac def 30 xyz
xyz abc 20 rst
xyz abc 10 rst
yzx cab 10 mno

-now i want to count the number of records excluding the duplicates!
in the above example 2nd & 5th, 3rd & 6th are duplicates.

if i make a count of total records without repetition, i must a get an
answer of 5 ie.(7-2)






Peo Sjoblom Wrote:

I would personally use the variant

=SUMPRODUCT(--(A1:A1000<""),1/COUNTIF(A1:A1000,A1:A1000&""))

otherwise you'll get DIV/0 errors if there are blank cells, it works
as
follows

the 1/countif part returns an array of numbers, if there is one value
unique
it will return 1,
if there are 2 values that are the same it will return 2 times 0.5 (1/2
=
0.5), if 3 it will return 0.333333, 4 0.25 and so on

assume we have this in A1:A10

1
2
3
4
65
6
1
2
3
4


it would be 6 unique values, the 1/countif returns

{0.5;0.5;0.5;0.5;1;1;0.5;0.5;0.5;0.5}

sumproduct will sum them to return 6, if we change the last number 4 to
1 so
there would be 3 1

{0.333333333333333;0.5;0.5;1;1;1;0.3333333333333 33;0.5;0.5;0.333333333333333}

still returns the total of 6

I believe former MVP Dave Hager was the originator of it although it
has
been converted from

=SUM(1/COUNTIF))

to sumproduct thus it can be entered normally

--

Regards,

Peo Sjoblom

Northwest Excel Solutions

Portland, Oregon




"Bill Kuunders" wrote in message
...

Bob, I check this news group frequently as a means to learn stuff.

Could you please explain why and how your formula works?

Thank You
--
Greetings from New Zealand
Bill K



"Bob Phillips" wrote in message
. ..

=SUMPRODUCT(1/COUNTIF(A1:A1000,A1:A1000))

--

HTH

Bob Phillips

(remove nothere from the email address if mailing direct)

"RJL0323"


wrote in

message


...

Hello All,
I have a question related to counting unique values in a column of
data. I will try to illustrate my question. I have a column of


data

with 1000 rows. In this column there are duplicated values. I


would

like to be able to use a function count how many unique values are


in

the column. Let's say there were 4 duplicates of 250 values in the
column. I would like to be able to write a function to calculate


the

250. I am very familiar with Excel and am able to acheive the


number

through subtotals and/or pivot tables. I know I can find how many
instances one specific value appears in the column through


sumproduct

and/or countif statements, but the function to calculate the number


of

unique values has really got me stumped.

Does anyone have any ideas?

Thanks in advance!!
RJ


--
RJL0323


------------------------------------------------------------------------

RJL0323's Profile:

http://www.excelforum.com/member.php...o&userid=19456

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  #10   Report Post  
Posted to microsoft.public.excel.worksheet.functions
Bob Phillips
 
Posts: n/a
Default Counting Unique Values

Bill,

I had a go at explaining it a while back in http://tinyurl.com/dhbxe. This
explanation is based upon the version that caters for blanks, but the
fundamental principle is the same.

--

HTH

Bob Phillips

(remove nothere from the email address if mailing direct)

"Bill Kuunders" wrote in message
...
Bob, I check this news group frequently as a means to learn stuff.

Could you please explain why and how your formula works?

Thank You
--
Greetings from New Zealand
Bill K



"Bob Phillips" wrote in message
...
=SUMPRODUCT(1/COUNTIF(A1:A1000,A1:A1000))

--

HTH

Bob Phillips

(remove nothere from the email address if mailing direct)

"RJL0323" wrote

in
message ...

Hello All,
I have a question related to counting unique values in a column of
data. I will try to illustrate my question. I have a column of data
with 1000 rows. In this column there are duplicated values. I would
like to be able to use a function count how many unique values are in
the column. Let's say there were 4 duplicates of 250 values in the
column. I would like to be able to write a function to calculate the
250. I am very familiar with Excel and am able to acheive the number
through subtotals and/or pivot tables. I know I can find how many
instances one specific value appears in the column through sumproduct
and/or countif statements, but the function to calculate the number of
unique values has really got me stumped.

Does anyone have any ideas?

Thanks in advance!!
RJ


--
RJL0323


------------------------------------------------------------------------
RJL0323's Profile:

http://www.excelforum.com/member.php...o&userid=19456
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Bill Kuunders
 
Posts: n/a
Default Counting Unique Values

Thank You Both

Peo and Bob

I appreciate your time and effort very much.

Bill Kuunders

"Bob Phillips" wrote in message
...
Bill,

I had a go at explaining it a while back in http://tinyurl.com/dhbxe. This
explanation is based upon the version that caters for blanks, but the
fundamental principle is the same.

--

HTH

Bob Phillips

(remove nothere from the email address if mailing direct)

"Bill Kuunders" wrote in message
...
Bob, I check this news group frequently as a means to learn stuff.

Could you please explain why and how your formula works?

Thank You
--
Greetings from New Zealand
Bill K



"Bob Phillips" wrote in message
...
=SUMPRODUCT(1/COUNTIF(A1:A1000,A1:A1000))

--

HTH

Bob Phillips

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"RJL0323" wrote

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Hello All,
I have a question related to counting unique values in a column of
data. I will try to illustrate my question. I have a column of data
with 1000 rows. In this column there are duplicated values. I would
like to be able to use a function count how many unique values are in
the column. Let's say there were 4 duplicates of 250 values in the
column. I would like to be able to write a function to calculate the
250. I am very familiar with Excel and am able to acheive the number
through subtotals and/or pivot tables. I know I can find how many
instances one specific value appears in the column through sumproduct
and/or countif statements, but the function to calculate the number of
unique values has really got me stumped.

Does anyone have any ideas?

Thanks in advance!!
RJ


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Bill Kuunders
 
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Default Counting Unique Values

One way.
enter =count(E2:E1002) in cell E1
select the range in question
go to ....data....filter....advanced filter....copy to another location
select E2
tick unique records only............. no need for a criteria range

Greetings from New Zealand
Bill K
"RJL0323" wrote in
message ...

Hello All,
I have a question related to counting unique values in a column of
data. I will try to illustrate my question. I have a column of data
with 1000 rows. In this column there are duplicated values. I would
like to be able to use a function count how many unique values are in
the column. Let's say there were 4 duplicates of 250 values in the
column. I would like to be able to write a function to calculate the
250. I am very familiar with Excel and am able to acheive the number
through subtotals and/or pivot tables. I know I can find how many
instances one specific value appears in the column through sumproduct
and/or countif statements, but the function to calculate the number of
unique values has really got me stumped.

Does anyone have any ideas?

Thanks in advance!!
RJ


--
RJL0323
------------------------------------------------------------------------
RJL0323's Profile:
http://www.excelforum.com/member.php...o&userid=19456
View this thread: http://www.excelforum.com/showthread...hreadid=513331



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