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I have a worksheet with numbers such as 175, 163, 250 etc. Is there a
formula without going back in and retyping all of these numbers that can turn them into a decimal number like this: 1.75, 1.63, 2.50. I've tried to multiply the cell by .01 but when I copy the formula down, it just copies just the result of that cell - Any help would be appreciated!!!! Thanks! -- Sandi Gardner |
#2
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Try this:
Put 0.01 in an empty cell Copy that cell Select the numbers that you want to be impacted. EditPaste Special Check: Values Check: Multiply click the [OK] button Does that help? *********** Regards, Ron XL2002, WinXP-Pro "Sandi" wrote: I have a worksheet with numbers such as 175, 163, 250 etc. Is there a formula without going back in and retyping all of these numbers that can turn them into a decimal number like this: 1.75, 1.63, 2.50. I've tried to multiply the cell by .01 but when I copy the formula down, it just copies just the result of that cell - Any help would be appreciated!!!! Thanks! -- Sandi Gardner |
#3
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![]() Sandi, Type .01 into a cell. Copy that. Highlight the entire range of values you want to multiply by .01. Paste Special - Multiply. Cheers, Steve -- SteveG ------------------------------------------------------------------------ SteveG's Profile: http://www.excelforum.com/member.php...fo&userid=7571 View this thread: http://www.excelforum.com/showthread...hreadid=511032 |
#4
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RON - HOW AWESOME ARE YOU!!!!!!!
Works like a charm!!!!!!! -- Sandi Gardner "Ron Coderre" wrote: Try this: Put 0.01 in an empty cell Copy that cell Select the numbers that you want to be impacted. EditPaste Special Check: Values Check: Multiply click the [OK] button Does that help? *********** Regards, Ron XL2002, WinXP-Pro "Sandi" wrote: I have a worksheet with numbers such as 175, 163, 250 etc. Is there a formula without going back in and retyping all of these numbers that can turn them into a decimal number like this: 1.75, 1.63, 2.50. I've tried to multiply the cell by .01 but when I copy the formula down, it just copies just the result of that cell - Any help would be appreciated!!!! Thanks! -- Sandi Gardner |
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