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#1
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![]() I would like to know how would I work out someone's age in number ("20") from having three seperate columns of: Day Month Year 14 March 1986 note, this is not in the form dd/mm/yyyy in *one* cell but in three seperate columns. I am thinking there may be two steps e.g. on step to get it into dd/mm/yyyy then another to pur it into age? Thanks in advance, Tim -- timmyc ------------------------------------------------------------------------ timmyc's Profile: http://www.excelforum.com/member.php...o&userid=31198 View this thread: http://www.excelforum.com/showthread...hreadid=508699 |
#2
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![]() Perhaps, =DATEDIF(A1&"-"&B1&"-"&C1,NOW(),"y") -- daddylonglegs ------------------------------------------------------------------------ daddylonglegs's Profile: http://www.excelforum.com/member.php...o&userid=30486 View this thread: http://www.excelforum.com/showthread...hreadid=508699 |
#3
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![]() Yeah thanks alot that really helped. Tim -- timmyc ------------------------------------------------------------------------ timmyc's Profile: http://www.excelforum.com/member.php...o&userid=31198 View this thread: http://www.excelforum.com/showthread...hreadid=508699 |
#4
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Try this, it has worked for me.
=YEAR(TODAY()-DATEVALUE(A1&B1&C1))-1900 |
#5
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one way with a lookup table
January 1 February 2 March 3 April 4 May 5 June 6 July 7 August 8 September 9 October 10 November 11 December 12 =DATEDIF(DATE(I5,VLOOKUP(H5,K4:L15,2,0),G5),NOW(), "y") -- Don Guillett SalesAid Software "timmyc" wrote in message ... I would like to know how would I work out someone's age in number ("20") from having three seperate columns of: Day Month Year 14 March 1986 note, this is not in the form dd/mm/yyyy in *one* cell but in three seperate columns. I am thinking there may be two steps e.g. on step to get it into dd/mm/yyyy then another to pur it into age? Thanks in advance, Tim -- timmyc ------------------------------------------------------------------------ timmyc's Profile: http://www.excelforum.com/member.php...o&userid=31198 View this thread: http://www.excelforum.com/showthread...hreadid=508699 |
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