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#1
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=IF(AND(F269,F2<90),25,IF(F2100,60,""))
=IF(AND(F269,F2<90),25,IF(F2100,60,""))
The above formula works well until I modify it as below: =IF(AND(F269,F2<75),25,IF(F275,F2.90),27,IF(F21 00,60,"")) It displays an error message indicating the problem is with 27, and I dont see why. Please help. Thanks -- Regards FangYR Malaysia |
#2
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=IF(AND(F269,F2<90),25,IF(F2100,60,""))
See if this variation works for you:
=IF(AND(F269,F2<75),25,IF(AND(F275,F2<90),27,IF( F2100,60,""))) It may need some tweaking, but it's syntactically correct. Does that help? *********** Regards, Ron XL2002, WinXP-Pro "FangYR" wrote: =IF(AND(F269,F2<90),25,IF(F2100,60,"")) The above formula works well until I modify it as below: =IF(AND(F269,F2<75),25,IF(F275,F2.90),27,IF(F21 00,60,"")) It displays an error message indicating the problem is with 27, and I dont see why. Please help. Thanks -- Regards FangYR Malaysia |
#3
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=IF(AND(F269,F2<90),25,IF(F2100,60,""))
There are a couple of problems. First, what is F2.90? Second, the
right-paren after the 90 closes off the 'then' clause of the first IF so that 27 looks like a fourth argument of the IF function, generating an error. Can you explain your intention in words? "FangYR" wrote: =IF(AND(F269,F2<90),25,IF(F2100,60,"")) The above formula works well until I modify it as below: =IF(AND(F269,F2<75),25,IF(F275,F2.90),27,IF(F21 00,60,"")) It displays an error message indicating the problem is with 27, and I dont see why. Please help. Thanks -- Regards FangYR Malaysia |
#4
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=IF(AND(F269,F2<90),25,IF(F2100,60,""))
If F2 is more than 69 and less than 90, then 25 points(or whatever), but if
F2is more than 100, then 60pts. Now I want something that can work out: if F2 is more than 60 and less than75, then 27, if F2 is more than 75 and less than 90, then 27, but if more than 100, then 60. -- Regards FangYR Malaysia "bpeltzer" wrote: There are a couple of problems. First, what is F2.90? Second, the right-paren after the 90 closes off the 'then' clause of the first IF so that 27 looks like a fourth argument of the IF function, generating an error. Can you explain your intention in words? "FangYR" wrote: =IF(AND(F269,F2<90),25,IF(F2100,60,"")) The above formula works well until I modify it as below: =IF(AND(F269,F2<75),25,IF(F275,F2.90),27,IF(F21 00,60,"")) It displays an error message indicating the problem is with 27, and I dont see why. Please help. Thanks -- Regards FangYR Malaysia |
#5
Posted to microsoft.public.excel.worksheet.functions
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=IF(AND(F269,F2<90),25,IF(F2100,60,""))
Hi
Try this: =IF(AND(F260,F2<90),27,IF(F2100,60)) What if F2 is between 90 and 100, or less than 60? Andy. "FangYR" wrote in message ... If F2 is more than 69 and less than 90, then 25 points(or whatever), but if F2is more than 100, then 60pts. Now I want something that can work out: if F2 is more than 60 and less than75, then 27, if F2 is more than 75 and less than 90, then 27, but if more than 100, then 60. -- Regards FangYR Malaysia "bpeltzer" wrote: There are a couple of problems. First, what is F2.90? Second, the right-paren after the 90 closes off the 'then' clause of the first IF so that 27 looks like a fourth argument of the IF function, generating an error. Can you explain your intention in words? "FangYR" wrote: =IF(AND(F269,F2<90),25,IF(F2100,60,"")) The above formula works well until I modify it as below: =IF(AND(F269,F2<75),25,IF(F275,F2.90),27,IF(F21 00,60,"")) It displays an error message indicating the problem is with "27", and I don't see why. Please help. Thanks -- Regards FangYR Malaysia |
#6
Posted to microsoft.public.excel.worksheet.functions
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=IF(AND(F269,F2<90),25,IF(F2100,60,""))
Hi Ron,
Thanks for that, but it only works with input "70", "75" and anything above "100" When I input "80" it give a blank. Regards FangYR Malaysia "Ron Coderre" wrote: See if this variation works for you: =IF(AND(F269,F2<75),25,IF(AND(F275,F2<90),27,IF( F2100,60,""))) It may need some tweaking, but it's syntactically correct. Does that help? *********** Regards, Ron XL2002, WinXP-Pro "FangYR" wrote: =IF(AND(F269,F2<90),25,IF(F2100,60,"")) The above formula works well until I modify it as below: =IF(AND(F269,F2<75),25,IF(F275,F2.90),27,IF(F21 00,60,"")) It displays an error message indicating the problem is with 27, and I dont see why. Please help. Thanks -- Regards FangYR Malaysia |
#7
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=IF(AND(F269,F2<90),25,IF(F2100,60,""))
Oh sorry Andy,
it should be: Now I want something that can work out: if F2 is more than 60 and less than75, then 25, if F2 is more than 75 and less than 90, then 27, but if more than 100, then 60. (if anything between 90-100, still 27, but not require yet) -- Regards FangYR Malaysia "Andy" wrote: Hi Try this: =IF(AND(F260,F2<90),27,IF(F2100,60)) What if F2 is between 90 and 100, or less than 60? Andy. "FangYR" wrote in message ... If F2 is more than 69 and less than 90, then 25 points(or whatever), but if F2is more than 100, then 60pts. Now I want something that can work out: if F2 is more than 60 and less than75, then 27, if F2 is more than 75 and less than 90, then 27, but if more than 100, then 60. -- Regards FangYR Malaysia "bpeltzer" wrote: There are a couple of problems. First, what is F2.90? Second, the right-paren after the 90 closes off the 'then' clause of the first IF so that 27 looks like a fourth argument of the IF function, generating an error. Can you explain your intention in words? "FangYR" wrote: =IF(AND(F269,F2<90),25,IF(F2100,60,"")) The above formula works well until I modify it as below: =IF(AND(F269,F2<75),25,IF(F275,F2.90),27,IF(F21 00,60,"")) It displays an error message indicating the problem is with "27", and I don't see why. Please help. Thanks -- Regards FangYR Malaysia |
#8
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=IF(AND(F269,F2<90),25,IF(F2100,60,""))
Yes, Thanks for that variation.
With some modifications, it works. =IF(AND(F2969,F29<74),25,IF(AND(F2974,F29<90),27 ,IF(F29100,60,""))) Thanks again Ron Conderre. -- Regards FangYR Malaysia "Ron Coderre" wrote: See if this variation works for you: =IF(AND(F269,F2<75),25,IF(AND(F275,F2<90),27,IF( F2100,60,""))) It may need some tweaking, but it's syntactically correct. Does that help? *********** Regards, Ron XL2002, WinXP-Pro "FangYR" wrote: =IF(AND(F269,F2<90),25,IF(F2100,60,"")) The above formula works well until I modify it as below: =IF(AND(F269,F2<75),25,IF(F275,F2.90),27,IF(F21 00,60,"")) It displays an error message indicating the problem is with 27, and I dont see why. Please help. Thanks -- Regards FangYR Malaysia |
#9
Posted to microsoft.public.excel.worksheet.functions
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=IF(AND(F269,F2<90),25,IF(F2100,60,""))
if F2 is more than 60 and less than75, then 25, if F2 is more than 75 and
less than 90, then 27, but if more than 100, then 60. =IF(F2<60,"",IF(F2<75,25,IF(F2<90,27,60))) (if anything between 90-100, still 27, but not require yet) =IF(F2<60,"",IF(F2<75,25,IF(F2<90,27,IF(F2<100,27, 60)))) or =IF(F2<60,"",IF(F2<75,25,IF(F2<100,27,60))) because you have the same output for 75-90 and 90-100. AND is not a good function to use with what you are doing, but if you have to use it your original function just had some syntax errors. "FangYR" wrote: Oh sorry Andy, it should be: Now I want something that can work out: if F2 is more than 60 and less than75, then 25, if F2 is more than 75 and less than 90, then 27, but if more than 100, then 60. (if anything between 90-100, still 27, but not require yet) -- Regards FangYR Malaysia "Andy" wrote: Hi Try this: =IF(AND(F260,F2<90),27,IF(F2100,60)) What if F2 is between 90 and 100, or less than 60? Andy. "FangYR" wrote in message ... If F2 is more than 69 and less than 90, then 25 points(or whatever), but if F2is more than 100, then 60pts. Now I want something that can work out: if F2 is more than 60 and less than75, then 27, if F2 is more than 75 and less than 90, then 27, but if more than 100, then 60. -- Regards FangYR Malaysia "bpeltzer" wrote: There are a couple of problems. First, what is F2.90? Second, the right-paren after the 90 closes off the 'then' clause of the first IF so that 27 looks like a fourth argument of the IF function, generating an error. Can you explain your intention in words? "FangYR" wrote: =IF(AND(F269,F2<90),25,IF(F2100,60,"")) The above formula works well until I modify it as below: =IF(AND(F269,F2<75),25,IF(F275,F2.90),27,IF(F21 00,60,"")) It displays an error message indicating the problem is with "27", and I don't see why. Please help. Thanks -- Regards FangYR Malaysia |
#10
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=IF(AND(F269,F2<90),25,IF(F2100,60,""))
Thanks for the feedback.....I'm glad you got that to work.
*********** Regards, Ron XL2002, WinXP-Pro "FangYR" wrote: Yes, Thanks for that variation. With some modifications, it works. =IF(AND(F2969,F29<74),25,IF(AND(F2974,F29<90),27 ,IF(F29100,60,""))) Thanks again Ron Conderre. -- Regards FangYR Malaysia "Ron Coderre" wrote: See if this variation works for you: =IF(AND(F269,F2<75),25,IF(AND(F275,F2<90),27,IF( F2100,60,""))) It may need some tweaking, but it's syntactically correct. Does that help? *********** Regards, Ron XL2002, WinXP-Pro "FangYR" wrote: =IF(AND(F269,F2<90),25,IF(F2100,60,"")) The above formula works well until I modify it as below: =IF(AND(F269,F2<75),25,IF(F275,F2.90),27,IF(F21 00,60,"")) It displays an error message indicating the problem is with 27, and I dont see why. Please help. Thanks -- Regards FangYR Malaysia |
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