IF statement problem
 

I have an if statement, and for either the true or false conditional
statements, I would like to type some text and have a number displayed.
This number is calculated by some formula.
For example, IF(MOD(ROW(),2)=0,"The current row; "ROW()" is even.",
"This row is odd.")
But the above syntax is incorrect. What is the correct syntax to
perform this type of operation?


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Kalabalana
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=IF(MOD(ROW(),2)=0,"The current row; "&ROW()&" is even.","The current row;
"&ROW()&" is odd.")


--

HTH

RP
(remove nothere from the email address if mailing direct)


"Kalabalana" wrote in message
...

I have an if statement, and for either the true or false conditional
statements, I would like to type some text and have a number displayed.
This number is calculated by some formula.
For example, IF(MOD(ROW(),2)=0,"The current row; "ROW()" is even.",
"This row is odd.")
But the above syntax is incorrect. What is the correct syntax to
perform this type of operation?


--
Kalabalana
------------------------------------------------------------------------
Kalabalana's Profile:
http://www.excelforum.com/member.php...o&userid=11433
View this thread: http://www.excelforum.com/showthread...hreadid=314582

One way:

=IF(MOD(ROW(),2)=0,"The current row; " & ROW() &" is even.",
"This row is odd.")


A variant:

="This row is " & IF(MOD(ROW(),2),"odd.","even.")

In article ,
Kalabalana wrote:

I have an if statement, and for either the true or false conditional
statements, I would like to type some text and have a number displayed.
This number is calculated by some formula.
For example, IF(MOD(ROW(),2)=0,"The current row; "ROW()" is even.",
"This row is odd.")
But the above syntax is incorrect. What is the correct syntax to
perform this type of operation?

=IF(MOD(ROW(),2)=0,"The current row " & ROW() & " is even.", "This row
is odd.")


--
crispbd
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View this thread: http://www.excelforum.com/showthread...hreadid=314582

excellent thank you all for your help


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Kalabalana
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Kalabalana's Profile: http://www.excelforum.com/member.php...o&userid=11433
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