Do you know of any of creating formulas using the "if" function more than
seven times. It is normally limited to seven, I need as many as 20

It's possible to use IF function 20 times given that you concatenate each
part, however it is hard to audit and if you indeed need many conditions you
might be better off using something else like a lookup table or index,
here's an example of how to bypass the 7 nested limits

=IF( A1=1,"a","")&IF(A1=3,"c","")&IF(A1=5,"e","")&and so on

however you might as well use a vlookup formula

=VLOOKUP(A1,{1,"a";3,"c";5,"e"},2,0)


--
Regards,

Peo Sjoblom

(No private emails please)


"JimB" wrote in message
...
Do you know of any of creating formulas using the "if" function more than
seven times. It is normally limited to seven, I need as many as 20

Thank you. What I am working on is a document we use at work to tally
production
and in this case there are 20 items. An example would be if item 301 were
completed, it would return a production value of 1.5. Here is the basic idea

=IF(B3=301,1.25,IF(B3=302,1.5,IF(B3=303,1.5,IF(B3= 304,1.75,IF(B3=305,1.25,IF(B3=306,1.5,IF(B3=307,0. 75,IF(B3=308,0.75,))))))))

"Peo Sjoblom" wrote:

It's possible to use IF function 20 times given that you concatenate each
part, however it is hard to audit and if you indeed need many conditions you
might be better off using something else like a lookup table or index,
here's an example of how to bypass the 7 nested limits

=IF( A1=1,"a","")&IF(A1=3,"c","")&IF(A1=5,"e","")&and so on

however you might as well use a vlookup formula

=VLOOKUP(A1,{1,"a";3,"c";5,"e"},2,0)


--
Regards,

Peo Sjoblom

(No private emails please)


"JimB" wrote in message
...
Do you know of any of creating formulas using the "if" function more than
seven times. It is normally limited to seven, I need as many as 20

Using vlookup you could use

=IF(B3="","",VLOOKUP(B3,{301,1.25;302,1.5;303,1.5; 304,1.75;305,1.25;306,1.5;307,0.75;308,0.75},2,0))

and there are no problems expanding that for 20 values, assume you put 301
in E1 and 1.25 in F1
302 in E2 and 1.5 in F2 and so on down to row 20, then you could use

=IF(B3="","",VLOOKUP(B3,E1:F20,2,0))

or hardcoded (I faked some more values using existing ones)

=IF(B3="","",VLOOKUP(B3,{301,1.25;302,1.5;303,1.5; 304,1.75;305,1.25;306,1.5;307,0.75;308,0.75;309,1. 25;310,1.5;311,1.5;312,1.75;313,1.25;314,1.5;315,0 .75;316,0.75;317,1.5;318,1.75;319,1.5;320,1.75},2, 0))


getting a tad long but it works, I would recommend using either a cell
reference like E1:F20 or named range
for the table, using concatenated IFs

=IF(OR(B3=301,B3=305),1.5,"")&IF(OR(B3=302,B3=303, B3=306),1.5,"")&IF(B3=304,1.75,"")&IF(OR(B3=307,B3 =308),0.75,"")

since some values are the same you can use OR and it might be possible that
you can use a regular if or formula without concatenating them, also you
could probably skip a bit using vlookup since some values are the same

--
Regards,

Peo Sjoblom

(No private emails please)


"JimB" wrote in message
...
Thank you. What I am working on is a document we use at work to tally
production
and in this case there are 20 items. An example would be if item 301 were
completed, it would return a production value of 1.5. Here is the basic
idea

=IF(B3=301,1.25,IF(B3=302,1.5,IF(B3=303,1.5,IF(B3= 304,1.75,IF(B3=305,1.25,IF(B3=306,1.5,IF(B3=307,0. 75,IF(B3=308,0.75,))))))))

"Peo Sjoblom" wrote:

It's possible to use IF function 20 times given that you concatenate each
part, however it is hard to audit and if you indeed need many conditions
you
might be better off using something else like a lookup table or index,
here's an example of how to bypass the 7 nested limits

=IF( A1=1,"a","")&IF(A1=3,"c","")&IF(A1=5,"e","")&and so on

however you might as well use a vlookup formula

=VLOOKUP(A1,{1,"a";3,"c";5,"e"},2,0)


--
Regards,

Peo Sjoblom

(No private emails please)


"JimB" wrote in message
...
Do you know of any of creating formulas using the "if" function more
than
seven times. It is normally limited to seven, I need as many as 20

I'd create another worksheet.

Put this in A1:Bxx

301 1.25
302 1.5
303 1.5
304 1.75
305 1.25
306 1.5
307 .75
308 .75

Then use a change to Peo's =vlookup() formula:

=if(b3="","",vlookup(b3,sheet2!a:b,2,false))



JimB wrote:

Thank you. What I am working on is a document we use at work to tally
production
and in this case there are 20 items. An example would be if item 301 were
completed, it would return a production value of 1.5. Here is the basic idea

=IF(B3=301,1.25,IF(B3=302,1.5,IF(B3=303,1.5,IF(B3= 304,1.75,IF(B3=305,1.25,IF(B3=306,1.5,IF(B3=307,0. 75,IF(B3=308,0.75,))))))))

"Peo Sjoblom" wrote:

It's possible to use IF function 20 times given that you concatenate each
part, however it is hard to audit and if you indeed need many conditions you
might be better off using something else like a lookup table or index,
here's an example of how to bypass the 7 nested limits

=IF( A1=1,"a","")&IF(A1=3,"c","")&IF(A1=5,"e","")&and so on

however you might as well use a vlookup formula

=VLOOKUP(A1,{1,"a";3,"c";5,"e"},2,0)


--
Regards,

Peo Sjoblom

(No private emails please)


"JimB" wrote in message
...
Do you know of any of creating formulas using the "if" function more than
seven times. It is normally limited to seven, I need as many as 20



--

Dave Peterson

On Mon, 17 Oct 2005 17:40:05 -0700, "JimB"
wrote:

Do you know of any of creating formulas using the "if" function more than
seven times. It is normally limited to seven, I need as many as 20

99/100 when this question is asked, the best solution is a lookup table.

Look at HELP for the VLOOKUP function, and/or post back with more details.


--ron