What is the syntax for sumif function with two criteria range and two criteria?

Use a different function ... SumProduct().

=SumProduct((A1:A100=criteria1)*(B1:B100=criteria2 )*C1:C100)
--
HTH,

RD
==============================================
Please keep all correspondence within the Group, so all may benefit!
==============================================


"AHANG JJJ" <AHANG wrote in message
...
What is the syntax for sumif function with two criteria range and two
criteria?

SUMIF and COUNTIF allow for only one criterion. You need array formulas or
SUMPRODUCT if you have multiple criteria. See the other response for one way.

On Fri, 30 Sep 2005 19:11:16 -0700, AHANG JJJ <AHANG
wrote:

What is the syntax for sumif function with two criteria range and two
criteria?

I have something like this:

A B C D

jim 4 jim 2
cathy 2 cathy 4
mary 5 mary 3

I would like to sum the values in B and D that corresponds to jim. I tried
=sumproduct((criteria1)*(criteria2)*(range B,D)), but this doesn't work. Any
help would be much appreciated.

Thanks!




"RagDyer" wrote:

Use a different function ... SumProduct().

=SumProduct((A1:A100=criteria1)*(B1:B100=criteria2 )*C1:C100)
--
HTH,

RD
==============================================
Please keep all correspondence within the Group, so all may benefit!
==============================================


"AHANG JJJ" <AHANG wrote in message
...
What is the syntax for sumif function with two criteria range and two
criteria?

Try...

=SUMIF(A1:C3,"Jim",B1:D3)

Hope this helps!

In article ,
oomyoo wrote:

I have something like this:

A B C D

jim 4 jim 2
cathy 2 cathy 4
mary 5 mary 3

I would like to sum the values in B and D that corresponds to jim. I tried
=sumproduct((criteria1)*(criteria2)*(range B,D)), but this doesn't work. Any
help would be much appreciated.

Thanks!

nope, didn't work...

I should get a value of 6, but I'm only getting 4. Any other ideas?

"Domenic" wrote:

Try...

=SUMIF(A1:C3,"Jim",B1:D3)

Hope this helps!

In article ,
oomyoo wrote:

I have something like this:

A B C D

jim 4 jim 2
cathy 2 cathy 4
mary 5 mary 3

I would like to sum the values in B and D that corresponds to jim. I tried
=sumproduct((criteria1)*(criteria2)*(range B,D)), but this doesn't work. Any
help would be much appreciated.

Thanks!

=SUMIF(A1:A3,"Jim",B1:B3) + SUMIF(C1:C3,"Jim",D1:D3)

HTH,
Bernie
MS Excel MVP


"oomyoo" wrote in message
...
nope, didn't work...

I should get a value of 6, but I'm only getting 4. Any other ideas?

"Domenic" wrote:

Try...

=SUMIF(A1:C3,"Jim",B1:D3)

Hope this helps!

In article ,
oomyoo wrote:

I have something like this:

A B C D

jim 4 jim 2
cathy 2 cathy 4
mary 5 mary 3

I would like to sum the values in B and D that corresponds to jim. I tried
=sumproduct((criteria1)*(criteria2)*(range B,D)), but this doesn't work. Any
help would be much appreciated.

Thanks!

i was thinking complicated instead of simple... thanks!

"Bernie Deitrick" wrote:

=SUMIF(A1:A3,"Jim",B1:B3) + SUMIF(C1:C3,"Jim",D1:D3)

HTH,
Bernie
MS Excel MVP


"oomyoo" wrote in message
...
nope, didn't work...

I should get a value of 6, but I'm only getting 4. Any other ideas?

"Domenic" wrote:

Try...

=SUMIF(A1:C3,"Jim",B1:D3)

Hope this helps!

In article ,
oomyoo wrote:

I have something like this:

A B C D

jim 4 jim 2
cathy 2 cathy 4
mary 5 mary 3

I would like to sum the values in B and D that corresponds to jim. I tried
=sumproduct((criteria1)*(criteria2)*(range B,D)), but this doesn't work. Any
help would be much appreciated.

Thanks!

The formula definitely returns the correct amount. Can you post the
exact formula you're using?

In article ,
oomyoo wrote:

nope, didn't work...

I should get a value of 6, but I'm only getting 4. Any other ideas?

"Domenic" wrote:

Try...

=SUMIF(A1:C3,"Jim",B1:D3)

Hope this helps!

In article ,
oomyoo wrote:

I have something like this:

A B C D

jim 4 jim 2
cathy 2 cathy 4
mary 5 mary 3

I would like to sum the values in B and D that corresponds to jim. I
tried
=sumproduct((criteria1)*(criteria2)*(range B,D)), but this doesn't work.
Any
help would be much appreciated.

Thanks!