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Excellent!!
=SUMPRODUCT(COUNTIF(INDIRECT({"C1","E1","H1","J1", "N1"}),"=1")) That's exactly what I needed. I knew there was a way to artifically create a range somehow. Thanks a million! -- Hmm...they have the Internet on COMPUTERS now! "Domenic" wrote: Try... =SUMPRODUCT(--ISNUMBER(MATCH(COLUMN(C1:N1)-COLUMN(C1)+1,{1,3,6,8,12},0)), --(C1:N1=1)) or =SUMPRODUCT(COUNTIF(INDIRECT({"C1","E1","H1","J1", "N1"}),"=1")) Also, if your data contains whole numbers, try... =INDEX(FREQUENCY((C1,E1,H1,J1,N1),0),2) Hope this helps! In article , MDW wrote: I think I used to know how to do this, but I'm on a new version of Excel (Xl2003) so maybe that wouldn't work anyway. I want to perform a simple COUNTIF, except the cells I want the function to examine are not contiguous. Essentially, I need the function to be something like the following: COUNTIF((C1,E1,H1,J1,N1),"=1") However that, and other variations I've tried, don't seem to work. This has got to be possible, but I think I need a pointer here. Thanks in advance. |
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